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Harrizon [31]
3 years ago
10

What can increase the gravitational potential energy of a object

Physics
1 answer:
love history [14]3 years ago
6 0

Answer:

Increase in mass and height

Explanation:

The gravitational potential energy of an object can increase if the mass and height of object is increased.

Gravitational potential energy is the energy due to the position of a body.

It is expressed as:

  Gravitational potential energy = mass x acceleration due gravity x height

Increasing mass and height will cause an increase in gravitational potential energy.

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The waves shown below represent sound waves. Which of the waves would have the highest-pitched sound?
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A rugby player runs with the ball directly toward his opponent's goal, along the positive direction of an x axis. He can legally
Over [174]

Answer:

minimum angle is 128.69°

Explanation:

given data

player velocity with respect ground v1 = 3.5 m/s

ball velocity with respect himself v2 = 5.6 m/s

to find out

smallest angle

solution

we know ball velocity with respect field will be

ball velocity = v1  +v2

ball velocity = 3.5 + 5.6 = 9.1m/s

we consider angle that player hit ball is θ

then by as per figure triangle

cosθ = \frac{v1}{v2}

cosθ = \frac{3.5}{5.6}

θ = 51.31

so minimum angle is 180 - 51.31 = 128.69°

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3 years ago
Definition of termperature in thermodynamics
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3 years ago
What location on earth experiences the most change the number of daylight hours?
CaHeK987 [17]
<span>The American Southwest and northeastern Africa are the two sunniest regions of the world, with the U.S. city of Yuma, Arizona, taking the crown as the sunniest place on Earth. Yuma, located where the state borders both California and Mexico, receives more than 4,000 sunlight hours per year and averages 11 sunny hours per day over the course of the year. Following closely behind Yuma is another U.S. city -- Phoenix -- which receives an average of 3,872 sunlight hours a year. The third sunniest spot on Earth is Aswan, Egypt, which has an average of 3,863 sunlight hours every year and averages 10.6 sunny hours per day.</span>
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3 years ago
Find the fundamental frequency and the next three frequencies that could cause standing-wave patterns on a string that is 30.0 m
maksim [4K]

Answer:

0.786 Hz, 1.572 Hz, 2.358 Hz, 3.144 Hz

Explanation:

The fundamental frequency of a standing wave on a string is given by

f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}

where

L is the length of the string

T is the tension in the string

\mu is the mass per unit length

For the string in the problem,

L = 30.0 m

\mu=9.00\cdot 10^{-3} kg/m

T = 20.0 N

Substituting into the equation, we find the fundamental frequency:

f=\frac{1}{2(30.0)}\sqrt{\frac{20.0}{(9.00\cdot 10^{-3}}}=0.786 Hz

The next frequencies (harmonics) are given by

f_n = nf

with n being an integer number and f being the fundamental frequency.

So we get:

f_2 = 2 (0.786 Hz)=1.572 Hz

f_3 = 3 (0.786 Hz)=2.358 Hz

f_4 = 4 (0.786 Hz)=3.144 Hz

6 0
3 years ago
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