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ANEK [815]
3 years ago
12

The weight of the North American P-51 Mustang airplane is 10,100 lb and its wing platform area is 233 ft2 . Calculate the wing l

oading (airplane weight per wing area) in both English engineering and SI units. Also, express the wing loading in terms of the nonconsistent (but commonly used) unit kgf/m2 (kilogram-force per square meter).
Physics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer

given,

weight of airplane,W = 10,100 lb

Wing area,A = 233 ft²

now,

Wing Loading Calculation in English engineering

        = \dfrac{W}{A}

        = \dfrac{10,100}{233}

        = 43.35 lb/ft²

Wing Loading in SI unit

        = 43.35\times \dfrac{4.448\ N}{1\ lb}\times (\dfrac{1\ ft}{0.3048})^2

        = 2075.51\ N/m^2

Wing loading in kgf/m²

      = \dfrac{2075.51}{9.81}

      = 211.57 kgf/m²

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(a) 0.165 m/s

The total initial momentum of the astronaut+capsule system is zero (assuming they are both at rest, if we use the reference frame of the capsule):

p_i = 0

The final total momentum is instead:

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v_a = 2.50 m/s is the velocity of the astronaut

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v_c is the velocity of the capsule

Since the total momentum must be conserved, we have

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m_a v_a + m_c v_c=0

Solving the equation for v_c, we find

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So, the change in speed of the capsule is 0.165 m/s.

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We can calculate the average force exerted by the capsule on the man by using the impulse theorem, which states that the product between the average force and the time of the collision is equal to the change in momentum of the astronaut:

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F=\frac{\Delta p}{\Delta t}=\frac{312.5 kg m/s}{0.600 s}=520.8 N

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(c) 25.9 J, 390.6 J

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

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m is the mass

v is the speed

For the astronaut, m = 125 kg and v = 2.50 m/s, so its kinetic energy is

K=\frac{1}{2}(125 kg)(2.50 m/s)^2=390.6 J

For the capsule, m = 1900 kg and v = 0.165 m/s, so its kinetic energy is

K=\frac{1}{2}(1900 kg)(0.165 m/s)^2=25.9 J

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