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3 years ago

In longitudinal waves the places where the coils are bunched together are called *

Physics

1 answer:

Firdavs [7]3 years ago

3 0

In longitudinal waves the places where the coils are bunched together are called *
Compressions

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The gauge pressure in the tires of your car is 210 kPa (30.5 psi) when the temperature is 25°C (77 °F). Several days later it is

DaniilM [7]

Under the assumption that the tires do not change in volume, apply Gay-Lussac's law:

P/T = const.

P = pressure, T = temperature, the quotient of P/T must stay constant.

Initial P and T values:

P = 210kPa + 101.325kPa

P = 311.325kPa (add 101.325 to change gauge pressure to absolute pressure)

T = 25°C = 298.15K

Final P and T values:

P = ?, T = 0°C = 273.15K

Set the initial and final P/T values equal to each other and solve for the final P:

311.325/298.15 = P/273.15

P = 285.220kPa

Subtract 101.325kPa to find the final gauge pressure:

285.220kPa - 101.325kPa = 183.895271kPa

The final gauge pressure is 184kPa or 26.7psi.

8 0

3 years ago

The figure shows the arrangement of master cylinder and slave cylinder of a part of braking system. The master cylinder piston,

Neko [114]

Answer:

a) 35 kPa

d) 140 N

c) 1) Increasing the brake fluid pressure

2) Increasing the slave piston surface area.

Explanation:

The parameters given are;

a) Force applied to the master cylinder piston = 28 N

Cross sectional area of the master cylinder piston = 8 cm² = 8 × 10⁻⁴ m²

The pressure P on the brake fluid is given by the formula for pressure as follows;

$P= \dfrac{Applied \ force}{Area \over \ which \ force \ is \ applied} = \dfrac{28 \, N}{8 \times 10^{-4} \, m^2} = 35,000 \, N/m^2 = 35,000 \, Pa$

The pressure on the brake fluid, P, produced by the master cylinder piston = 35,000 Pa = 35 kPa

b) Given that the area of the slave piston = 40 cm² = 0.004 m², we have from the formula for pressure, P;

$P= \dfrac{Applied \ force}{Area \over \ which \ force \ is \ applied} = \dfrac{Applied \ force}{4 \times 10^{-3} \, m^2} = 35,000 \, N/m^2$

Therefore;

Applied force on the slave piston = 4 × 10⁻³ m² × 35,000 N/m² = 140 N

c) The force, F produced by the slave cylinder piston is given by the relation;

F = Pressure × Area

Therefore, the two ways of increasing the force produced by the slave cylinder piston is as follows;

1) Increasing the pressure in the brake fluid by increasing the force exerted by the master cylinder piston

2) Increasing the surface area of the slave piston.

4 0

3 years ago

7. Two workers must pick up bricks that lie on the ground and place them on a worktable. They each

sdas [7]

Answer:

Same work is done by the two workers

The first worker exerts more power than the second person

Explanation:

Work is the product of force and distance moved in the direction of the applied force

Power is the rate at which work is done

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3 years ago

Explain why the gravitational acceleration of any object near Earth is the same no matter what the mass of the object is.

Murljashka [212]

Gravity is 9.8m/s2. Hence, we have to remember that weight and mass are two different things first. Mass is how much matter or the amount of matter an object contains and is constant. While weight is the gravitational force of the object’s mass and the earth’s gravity, in formula, W=mg. Weight varies from each planet or satellite an object is in. In reference to earth’s gravitational acceleration is the same because of the pull of the earth’s core is a constant speed of 9.8m/s2. It will not change. Hence multiplying this constant to the mass of the object equals the whole force or weight of the earth to pull this object towards it core. So mass is never the issue, weight is. Additionally, for every second, an object falls increases by 9.8 x mass = weight!

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3 years ago

Why does precipitation<br> occur when warm air rises?

Marat540 [252]

Answer:

the warm air rises, cools and condenses to form clouds

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2 years ago