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jekas [21]
3 years ago
8

Consider a simple ideal Rankine cycle with fixed turbine inlet conditions. What is the effect of lowering the condenser pressure

on: (a) Pump work input; (b) Turbine work output; (c) Heat supplied; (d) Heat rejected; (e) cycle efficiency; (f) Moisture content at turbine exit
Physics
1 answer:
mr Goodwill [35]3 years ago
8 0

Answer:

The effect of lowering the condenser pressure on different parameters is explained below.

Explanation:

The simple ideal Rankine cycle is shown in figure.

Effect of lowering the condenser pressure on

(a). Pump work input :- By lowering the condenser pressure the pump work increased.

(b) Turbine work output :- By lowering the condenser pressure the turbine work increased.

(c). Heat supplied :- Heat supplied increases.

(d). Heat rejected :- The heat rejected may increased  or decreased.

(e). Efficiency :- Cycle  efficiency is increased.

(f). Moisture content at turbine exit :- Moisture content increases.

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20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What's the new volu
Anna71 [15]

Answer:

B. V_{f}= 10\,cubic\,inches

Explanation:

Assuming we are dealing with a perfect gas, we should use the perfect gas equation:

PV=nRT

With T the temperature, V the volume, P the pressure, R the perfect gas constant and n the number of mol, we are going to use the subscripts i for the initial state when the gas has 20 cubic inches of volume and absolute pressure of 5 psi, and final state when the gas reaches 10 psi, so we have two equations:

P_{i}V_{i}=n_{i}RT_{i} (1)

P_{f}V_{f}=n_{f}RT_{f} (2)

Assuming the temperature and the number of moles remain constant (number of moles remain constant if we don't have a leak of gas) we should equate equations (1) and (2) because T_{i}=T_{f}, n_{i}=n_{f} and R is an universal constant:

P_{i}V_{i}= P_{f}V_{f}, solving for V_{f}

V_{f} =\frac{P_{i}V_{i}}{P_{f}} =\frac{(5)(20)}{10}

V_{f}= 10 cubic\,inches

6 0
3 years ago
A mad scientist wants to collect massive amounts of charge on basketball sized aluminum balls. The scientist wants to place 6 C
vitfil [10]

The distance between two basket ball sized aluminium balls is 9714 m.

Explanation:

Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force .

Coulomb's law formula => F = (k * Qb1 * Qb2)/r²

Given data :-

charge on ball 1 Qb1 = 6C

charge on ball 2 Qb2 = 14C

Force exerted F = 8000 N

k =  8.988 x 10^9 Nm²C−²(coulomb's constant).

substituting given values in the coulomb's formula

8000 = (( 8.988 x 10^9)*6*14)/r²

shifting r and 8000 to other sides

r² = (756 * 10^9)/8000

r = 9714 m.

Therefore the distance between two balls is r = 9714 m.

4 0
3 years ago
A sinusoidal wave has the following wave function: y(x,t) = (2.5 m) sin((3.0 m ) x - (24 s-')t + Tt/2] What is the frequency of
vladimir1956 [14]

Answer:

Frequency of the wave is 3.8 hertz.

Explanation:

It is given that, the sinusoidal wave has following wave equation as :

y(x,t)=(2.5\ m)sin[(3\ m^{-1})x-(24\ s^{-1})t+\pi/2]

The general equation for the sinusoidal wave is :

y=A\ sin(kx-\omega t+\phi)

Where

A is the amplitude

k is the constant

\omega is the angular frequency

\phi is the phase difference

Since, \omega=24\ s^{-1}

2\pi f=24

f=\dfrac{24}{2\pi}=3.81\ Hz

or

f = 3.8 Hz

So, the frequency of the wave is 3.8 hertz. Hence, this is the required solution.

8 0
3 years ago
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