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Xelga [282]
2 years ago
10

100 °C is a greater temperature than which of the following?

Physics
1 answer:
ohaa [14]2 years ago
6 0
When somebody hands you a Celsius°, it's easy to find the equivalent Fahrenheit°.

Fahrenheit° = (1.8 · Celsius°) + 32° .

So 100°C works out to 212°F.  

It's also easy to find the equivalent Kelvin.  Just add 273.15 to the Celsius.

So now you can see that  100°C  is equal to  A  and  D,
and it's less than  B .

The only one it's greater than is  C .
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Because I can't control eating lots of rice

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Which surface feature of the moon is characterized by mountainous areas?
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a wooden block has a mass of 1.2 kg, a specific heat of 710, and is at a temperature of 25*C. what is the block's final temperat
mash [69]

The final temperature of the block is 27.5^{\circ} C

Explanation:

The amount of thermal energy Q supplied to a substance is related to the increase in temperature of the substance, \Delta T, according to the equation

Q=mC_s \Delta T

where:

m is the mass of the substance

C_s is the specific heat capacity of the substance

In this problem, we have:

m = 1.2 kg is the mass of the block

Q = 2,130 J is the amount of energy supplied to the block

C_s = 710 J/kg^{\circ}C is the specific heat capacity of the block

Solving for \Delta T, we find the increase in temperature:

\Delta T = \frac{Q}{m C_s}=\frac{2130}{(1.2)(710)}=2.5^{\circ}C

And since the initial temperature was

T_i = 25^{\circ}C

The final temperature will be

T_f = T_i + \Delta T = 25+2.5=27.5^{\circ} C

Learn more about specific heat capacity:

brainly.com/question/3032746

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#LearnwithBrainly

8 0
3 years ago
3. As the ice melts into liquid water, what happens to the kinetic energy of the particles in the sample?
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Answer:

As ice melts into water, kinetic energy is being added to the particles. This causes them to be 'excited' and they break the bonds that hold them together as a solid, resulting in a change of state: solid -> liquid.

Explanation:

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A source charge of 3 µC generates an electric field of 2.86 × 105 N/C at the location of a test charge. Using k = 8.99 × 109N.m^
Nataliya [291]
Variables:

Source charge, Q = 3 micro C = 3 * 10^ - 6 C

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d = distance = ?

Formula:

E = K * Q / (d^2) => d^2 = K * Q / E

=> d^2 = 8.99 * 10^9 N * m^2 / C * 3 * 10^ -6 C / (2.86 * 10^ 5 N/C)

d^2 = 9.43 * 10 ^ -2  m^2

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Answer: 0.307 m

Note: it is a long distance due to the Electric field is very low
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