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3 years ago

Please help I got 20mins

Mathematics

1 answer:

Llana [10]3 years ago

8 0

Answer/Step-by-step explanation:

Scale factor: 1/4

AC = DF and 10 ÷ 2.5 = 4

10 x 1/4 = 2.5

DE length: 5

AB = DE

20 x 1/4 = 5

BC length: 30

EF = BC

(Because EF is the dilation) 7.5 x 4 = 30

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Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

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c is the hypotenuse (the greater side)

In this problem

Let

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substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

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$b=\sqrt{120}\ cm$

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we have that

Jayden's Work

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

Sheridan's Work

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct

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Please help I got 20mins​

Please help I got 20mins