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Yuri [45]
3 years ago
9

How many grams of kno3 pellets must be dissolved in water in order to prepare 100 ml of a 8 m kno3?

Chemistry
1 answer:
Montano1993 [528]3 years ago
4 0
In 8M of KNO3, there are x moles of KNO3 divided by (100/1000)L of water (because molarity is concentration, given by no. of moles divided by total volume in liters).

by changing the subject of formula, x = 0.1L × 8M = 0.8mol

given the no. of mol of KNO3, mass of KNO3 is given by no. of mol multipled by the relative molecular mass of KNO3.

mass = 0.8mol × 101.10g/mol (or whatever your periodic table says) = 80.88g
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If you start with 0.30 m Mn₂ , at 12.5 pH, free Mn₂ concentration be equal to 4.6 x 10⁻¹¹ m

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Ksp [Mn(OH)₂] = 4.6 x 10⁻¹⁴ (standard value)

Write the ionic equation

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We will calculate the concentration of OH⁻ by using Ksp expression

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