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Nonamiya [84]
3 years ago
12

Assume the following is a neutral atom.

Chemistry
1 answer:
Lena [83]3 years ago
4 0

Answer:

2. carbon

Explanation:

carbon should be the answer

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A 6.0 M HCl solution is available. What volume is needed to make 6.00 L of 1.00 M<br> solution?
Ket [755]

Answer:

The volume of the stock solution needed is 1L

Explanation:

Step 1:

Data obtained from the question. This include the following:

Concentration of stock solution (C1) = 6M

Volume of stock solution needed (V1) =?

Concentration of diluted solution (C2) = 1M

Volume of diluted solution (V2) = 6L

Step 2:

Determination of the volume of the stock solution needed.

With the dilution formula C1V1 = C2V2, the volume of the stock solution needed can be obtained as follow:

C1V1 = C2V2

6 x V1 = 1 x 6

Divide both side by 6

V1 = 6/6

V1 = 1L

Therefore, the volume of the stock solution needed is 1L

5 0
3 years ago
The complete orbital notation diagram of an atom is shown.
Yuki888 [10]

Answer:

Explanation:

From the description provided by the statement of the problem, we can easily solve for the values of the angular momentum quantum number.

Let us represent the atom as J:

In atom J, we have five sub-orbitals in which there 9 electrons. From the designation used to represent sublevels, we can write the notation as below:

             J = 10 electrons = 1s² 2s² 2p⁵

The s-sublevel can only contain 2 electrons

p-sublevel can contain 6 electrons but we have just 5 electrons in there.

Now, to find the angular momentum quantum number, we need to understand what this quantum number denotes.

This quantum number is also known as azimuthal or secondary quantum number. It gives the shape of the orbitals in subshells accomodating electrons. This quantum number is designated by (l).

         l (n-1)            name of orbital               shape of orbital

             0                     s                                   spherical

             1                     p                                    dumb-bell

             2                    d                                    double dumb-bell

             3                    f                                      complex

J  = 1s² 2s² 2p⁵

where 1 and 2 coefficients are the principal quantum numbers(n).

            s and p are the shape of the orbitals

For 1s², the l vaue is 0 because the electron is in the s orbital

     2s² the l value is 0, 1 and the electron can be in the s or p orbitals

     2p⁵ the l value is 0, 1 and the electrons can be in the s or p orbitals

The quantum number gives the shape of the orbital.

8 0
3 years ago
What is ejected from the nucleus during alpha decay?
Aloiza [94]
Hi

Alpha decay is a type of radioactive decay.
So, when Alpha decay goes through a process called "radioactive process", two neutrons and two protons comes together and is ejected from the nucleus of a radioactive atom.

Hope this helped :)
7 0
4 years ago
What does the mass number of an element represent?
madreJ [45]

Answer:

The mass number tells us the number (the sum of nucleons) of protons and neutrons in the nucleus of an atom. The atomic number (also known as the proton number) is the number of protons found in the nucleus of an atom. It is traditionally represented by the symbol z

Explanation:

8 0
3 years ago
Read 2 more answers
When 50.0 g iron(III) oxide reacts with carbon monoxide, 32.5 g iron is produced. What is the percent yield of the reaction?
scoray [572]

Answer:

92.9%

Explanation:

You have been given the actual yield of the reaction. First, you need to find the theoretical yield of the reaction. To do this, you need to (1) convert grams Fe₂O₃ to moles Fe₂O₃ (via molar mass from periodic table values), then (2) convert moles Fe₂O₃ to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass).

Once you have found the theoretical yield, you need to use the percent yield equation to calculate the final answer. This number should have 3 sig figs to match the given values.

<u>(Step 1)</u>

Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (Fe₂O₃): 159.684 g/mol

1 Fe₂O₃(s) + 3 CO(g) ---> 2 Fe(s) + 3 CO₂(g)


Molar Mass (Fe):
55.845 g/mol

50.0 g Fe₂O₃           1 mole              2 moles Fe           55.845 g
--------------------  x  ------------------  x  ---------------------  x  ----------------  = 35.0 g Fe
                               159.684 g         1 mole Fe₂O₃          1 mole

<u>(Step 2)</u>

                                 Actual Yield
Percent Yield  =  ---------------------------  x  100%
                             Theoretical Yield

                                32.5 g Fe
Percent Yield  =  ----------------------  x  100%  =  92.9%
                                35.0 g Fe

4 0
2 years ago
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