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Natasha2012 [34]
3 years ago
10

How many days does it take 16.Og of Gold-198 to decay to 1.0g? (each half-

Chemistry
1 answer:
forsale [732]3 years ago
4 0

Answer:

10.8 days (3 sig.figs.)

Explanation:

All radioactive decay is 1st order decay defined by the expression A = A₀e^-kt

which is solved for time of decay (t) => t = ln(A/A₀) / -k

A = final weight = 1.0 gram

A₀ = initial weight = 16.0 grams

k = rate constant = 0.693/t(1/2) = 0.693/2.69 days = 0.258 days⁻¹

t = ln(1/16) / -0.258da⁻¹ = (-2.77/-0.258) days = 10.74646792 days (calculator)

≅ 10 days (1 sig. fig. based on given 1 gram mass)

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How to write steam in chemical equations???

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C-12 and C-13 are naturally-occurring isotopes of the element carbon. C-12 occurs 98.88% of the time and C-13 occurs 1.108% of t
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c) (12×0.9889) + (13×0.01108)

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What is the critical angle for the interface between water and diamond?
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<h3>What is the critical angle?</h3>

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It strikes the border without being completely reflected within the first medium is called the critical angle in optics.

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A 3.5L container has a gas pressure of 5.3atm. If the volume is decreases to 1.4L. What will be the new pressure inside the cont
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