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Ierofanga [76]
2 years ago
14

A diode for which the forward voltage drop is 0.7 V at 1.0 mA is operated at 0.5 V. What is the value of the current

Physics
1 answer:
Vesnalui [34]2 years ago
4 0

Answer:

the current value is 0.335 \mu A

Explanation:

The computation of the value of the current is given below:

z_i = I_s e^{\frac{0.7}{ut} }= 10^{-3}\\\\Z_z = I_s e^{\frac{0.5}{ut} }\\\\\frac{Z_z}{Z_i}= \frac{Z_z}{10^{-3}}  = e^{\frac{0.5\times 0.7}{0.025} }\\\\= 0.335 \mu A

Hence, the current value is 0.335 \mu A

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Answer:

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The charged particle (which is positively charged) moves from point A to B, and its kinetic energy increases: it means that the particle is following the direction of the field, so its potential energy is decreasing (because it's been converted into potential energy), therefore it is moving from a point at higher potential (A) to a point at lower potential (B). This means that the value

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We can calculate the potential difference between the two points by using the law of conservation of energy:

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\Delta V=V_b-V_a = -\frac{\Delta K}{q}=-\frac{1.6\cdot 10^{-18} J}{3.2\cdot 10^{-19} C}=-5 V

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