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Ierofanga [76]
2 years ago
14

A diode for which the forward voltage drop is 0.7 V at 1.0 mA is operated at 0.5 V. What is the value of the current

Physics
1 answer:
Vesnalui [34]2 years ago
4 0

Answer:

the current value is 0.335 \mu A

Explanation:

The computation of the value of the current is given below:

z_i = I_s e^{\frac{0.7}{ut} }= 10^{-3}\\\\Z_z = I_s e^{\frac{0.5}{ut} }\\\\\frac{Z_z}{Z_i}= \frac{Z_z}{10^{-3}}  = e^{\frac{0.5\times 0.7}{0.025} }\\\\= 0.335 \mu A

Hence, the current value is 0.335 \mu A

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4.3s, 4.6s, 4.6s, 4.8s, 5.1s, 5.8s

The two outliers are obviously 4.3s and 5.8s; An outlier is a value in a statistical sample which does not fit a pattern that describes most other data point. Outliers make the average value complicated. So, it is usually better for data to be precise with data points spreading out around a small area.

So, the mean is the average of the four remaining data points after removing the outliers.

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So, the value recorded should be 4.775s, 4.78s or 4.8s depending on the number of decimal places allowed.

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