Answer:
It will cost 1.9$ to neutralize the waste sulfuric acid
Explanation:
<u>Step 1:</u> The neutralization reaction
H2SO4(aq) + Ca(OH)2 (s) → CaSO4(s) + 2H2O
<u>Step 2:</u> Calculate the molar mass of Ca(OH)2
Molar mass of Ca = 40.08 g/mole
Molar mass of O = 16 g/mole
Molar mass of H = 1.01 g/mole
Molar mass of Ca(OH)2 = 40.08 + 2*16 + 2*1.01 =74.1 g/mole
<u>Step 3:</u> Convert gallons to liters
2.77 gallons of H2SO4 = 10.48559 Liters H2SO4
<u>Step 4:</u> Calculate number of moles of H2SO4
Molarity = moles / liters
2.10 M = moles / 10.48559L
number of moles = 2.10 * 10.48559 =22.02 moles
<u>Step 5:</u> Calculate the number of moles of Ca(OH)2
H2SO4(aq) + Ca(OH)2 (s) → CaSO4(s) + 2H2O
For 1 mole of H2SO4 consumed we need 1 mole of Ca(OH)2
This means we need 22.02 moles of Ca(OH)2
<u>Step 6:</u> Calculate mass of Ca(OH)2
mass of Ca(OH)2 =number of moles * Molar mass of Ca(OH)2
mass of Ca(OH)2 = 22.02 moles * 74.1 g/moles = 1631.682 grams
<u>Step 7:</u> Convert grams to pounds
1631.682 grams/ 453.592 = 3.5972 pounds
<u>Step 8:</u> Calculate the cost
price Price per pound = 0.53$
Price for 3.5972 pounds = 0.53 * 3.5972 = 1.906516 ≈1.9$
It will cost 1.9$ to neutralize the waste sulfuric acid