As a result of doubled resistance, current will be halved. 
As we know, Ohm's law inversely relates current and resistance to each other. The equation is as follows - 
V = I*R, where V is voltage, I is current and R is resistance. 
As the question mentions no change in any other parameter, let's assume I₁ and I₂ be initial and final current and R₁ and R₂ initial and final resistance. 
So, R₂ will be 2R₁ as it is doubled. 
Now, equating the values and finding out the value of final current. 
I₁R₁ =  I₂R₂
Keep the value of R₂ 
I₁R₁ =  I₂2R₁
Cancelling R₁ as it is common on both sides of equation. 
So, we get - I₁ =  2I₂
I₂ = I₁/2
Thus, as can be seen above, final current will be half of initial current. 
Learn more about Ohm's law and relation between current, voltage and resistance -
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Answer:
A. Heat flows from an object at higher temperature to an object at lower temperature
Explanation:
The option A obeys the 2nd law of thermodynamics. The heat will flow from the object at higher temperature to the object at Lower temperature till they reach an equilibrial state.
 Heat doesn’t necessarily flow from an object with higher thermal energy to an object with lower thermal energy because an object has a higher thermal energy when it’s mass is more than the other. This makes B wrong.
C is wrong because heat moves from an object with higher temperature to objects with Lower temperature regardless of the state of matter.
 
        
             
        
        
        
Static friction
hope this helps
        
                    
             
        
        
        
<span>The middle life crisis occurs for men at age of 39 and for women at age of 44. At this age, people start realizing that they are getting older and experience some physical changes which seem distressful for them.</span>
<span> It affects the sense of accomplishment and progress in career. Due to a midlife crisis, people start engaging in activities to cope with the reality such as wearing clothes that are fashionable, dating someone etc. Yes, I think I will also go through one because it happens with everyone in this age.  It can be avoided by accepting the fact that these changes are reality and everyone have to face it one day.</span>
 
        
             
        
        
        
Answer:
Approximately  (assuming that the melting point of ice is
 (assuming that the melting point of ice is  .)
.) 
Explanation:
Convert the unit of mass to kilograms, so as to match the unit of the specific heat capacity of ice and of water.

The energy required comes in three parts:
- Energy required to raise the temperature of that  of ice from of ice from to to (the melting point of ice.) (the melting point of ice.)
- Energy required to turn  of ice into water while temperature stayed constant. of ice into water while temperature stayed constant.
- Energy required to raise the temperature of that newly-formed  of water from of water from to to . .
The following equation gives the amount of energy  required to raise the temperature of a sample of mass
 required to raise the temperature of a sample of mass  and specific heat capacity
 and specific heat capacity  by
 by  :
:
 ,
, 
where
 is the specific heat capacity of the material, is the specific heat capacity of the material,
 is the mass of the sample, and is the mass of the sample, and
 is the change in the temperature of this sample. is the change in the temperature of this sample.
For the first part of energy input,  whereas
 whereas  . Calculate the change in the temperature:
. Calculate the change in the temperature:
 .
.
Calculate the energy required to achieve that temperature change:
 .
.
Similarly, for the third part of energy input,  whereas
 whereas  . Calculate the change in the temperature:
. Calculate the change in the temperature:
 .
.
Calculate the energy required to achieve that temperature change:
 .
.
The second part of energy input requires a different equation. The energy  required to melt a sample of mass
 required to melt a sample of mass  and latent heat of fusion
 and latent heat of fusion  is:
 is:
 .
.
Apply this equation to find the size of the second part of energy input:
 .
.
Find the sum of these three parts of energy:
 .
.