The given terms are :
Current = 0.8 Amperes
Time = 3 minutes = 3 × 60 = 180 seconds
we know that,
now, let's solve for charge (q) :
Total Charge (q) = 144 Coulombs
Reaction force is the ball pulling up on the Earth. Every action has an equal and opposite reaction, so when the Earth pulls on the baseball, the baseball pulls back on the Earth with equal force
To start with solving this
problem, let us assume a launch angle of 45 degrees since that gives out the
maximum range for given initial speed. Also assuming that it was launched at
ground level since no initial height was given. Using g = 9.8 m/s^2, the
initial velocity is calculated using the formula:
(v sinθ)^2 = (v0 sinθ)^2
– 2 g d
where v is final
velocity = 0 at the peak, v0 is the initial velocity, d is distance = 11 m
Rearranging to find for
v0: <span>
v0 = sqrt (d * g/ sin(2 θ)) </span>
<span>v0 = 10.383 m/s</span>
Answer:
The Answer is B because the material the object is made of, the position, or the color have absolutely nothing to do with gravitational potential energy
Answer:
1.12×10⁻⁵ C and 2.24×10⁻⁵ C.
Explanation:
From coulomb's law,
F = kAB/r².............................. Equation 1
Where F = Force exerted by each charge, A = charge at point A, B = charge at point B, r = distance of separation between the points, k = constant of proportionality.
Given: F = 47 N, r = 22 cm = 0.22 m.
Constant: k = 9.0×10⁹ Nm²/C²
Let: B = q, the A = 2q.
Substituting these values into equation 1,
47 = 9.0×10⁹(q×2q)/0.22²
47 = 18×10⁹(q²)/0.0484
q² = (47×0.0484)/(18×10⁹)
q² = 0.126×10⁻⁹
q² = 1.26×10⁻¹⁰
q = √( 1.26×10⁻¹⁰)
q = 1.12×10⁻⁵ C
The charge at point A = 2q = 2× 1.12×10⁻⁵ = 2.24×10⁻⁵ C.
Hence the charges are 1.12×10⁻⁵ C and 2.24×10⁻⁵ C.
