Answer:
Explanation:
Through food chains, the carbon that is in plants moves to the animals that eat them. Animals that eat other animals get the carbon from their food too. Carbon moves from plants and animals to soils. When plants and animals die, their bodies, wood and leaves decays bringing the carbon into the ground.
The pH of the weak acid is 6.93.
Given,
K= 1.15 *
c=0.102
[H]= K*c= 1.15 * * 0.102= 0.1173 *
p[H]= -log[H]= 6.93
<h3>Weak acid</h3>
A weak acid is one that partially separates into its ions in water or an aqueous solution. A strong acid, on the other hand, completely splits into its ions in water. The conjugate base of a weak acid is also a weak base, and vice versa for the conjugate acid of a weak base. Weak acids have a higher pH than strong acids at the same concentration. Simple arrows pointing left to right are used to represent the reaction of a strong acid ionising in water. On the other hand, a weak acid ionising in water has a double arrow reaction arrow, indicating that both the forward and reverse reactions take place at equilibrium.
Learn more about Weak acid here:
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Water could be made
to boil at 105 degrees Celsius instead of 100 degrees Celsius by taking
the sample to a higher altitude. Pressure is directly proportional to
temperature. So when you bring water into higher altitude, you are increasing
the external pressure and therefore increase the boiling point.
You need to use the Ka for the acetic acid and the equilibrium equation.
Ka = 1.85 * 10^ -5
Equilibrium reaction: CH3COOH (aq) ---> CH3COO(-) + H(+)
Ka = [CH3COO-][H+] / [CH3COOH]
Molar concentrations at equilibrium
CH3COOH CH3COO- H+
0.50 - x x x
Ka = x*x / (0.50 - x) = x^2 / (0.50 - x)
Given that Ka is << 1 => 0.50 >> x and 0.50 - x ≈ 0.50
=> Ka ≈ x^2 / 0.50
=> x^2 ≈ 0.50 * Ka = 0.50 * 1.85 * 10^ -5 = 0.925 * 10^ - 5 = 9.25 * 10 ^ - 6
=> x = √ [9.25 * 10^ -6] = 3.04 * 10^ -3 ≈ 0.0030
pH = - log [H+] = - log (x) = - log (0.0030) = 2.5
Answer: 2.5
Exothermic. Exothermic exo meaning out, release heat while endothermic, endo as in in, take in heat.
