Question

If a body is thrown up with an initial velocity 'u' and covers a maximum height of 'h' , then 'h' is equal to u²/2g

Answer 1

GIVEN:

s = h , v = 0m/s and a = - g

ANSWER:

We know the equation, v² - u² = 2as.

Hence, - u² = - 2gh

so, maximum height attained is

• h = u²/2g.

Answer 2

Answer:

1/2 m u^2     initial Kinetic Energy of body

m g h        Potential Energy body attains as it rises to height

1/2 m u^2 = m g h      conversion of KE to PE

h = u^2 / ( 2  g)