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3 years ago

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What is the Index of refraction of a material of the speed of light in that materials is 2.251 x 10^8 m/s ? Use 3.00 x 10^8 m/s

for the speed of light in

1 answer:

Sladkaya [172]3 years ago

7 0

Answer:

1.33

Explanation:

$n = \frac{c}{v} \\ n = \frac{3 \times 10 {}^{8} }{2.251 \times {10}^{8} } \\ n = 1.33$

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A severe storm has an average peak wave height of 16.4 feet for waves hitting the shore. suppose that a storm is in progress wit

Agata [3.3K]

Before we answer this question, let us first understand what alternate hypothesis is.

The alternative hypothesis is the hypothesis which is used in the hypothesis testing and this is opposite to the null hypothesis. This is the test hypothesis which is usually taken to be that the observations are the result of a real effect in an experiment.

In this case since what we want to set up is the statistical test to see if the waves are dying down, then this means we are trying to determine if the wave height are decreasing, so lesser than 16.4 feet. Therefore:

The alternative hypothesis would state (ANSWER)

Ha: μ less than 16.4 feet and P-value area is on the left of the mean.

While the null hypothesis is the opposite and would state

H0: mu equals 16.4 feet

4 0

3 years ago

At what speed, as a fraction of c , is a particle's total energy twice its rest energy

WINSTONCH [101]

The rest energy of a particle is
$E_0=m_0 c^2$
where $m_0$ is the rest mass of the particle and c is the speed of light.

The total energy of a relativistic particle is
$E=mc^2 = \frac{m_0 c^2}{ \sqrt{1- \frac{v^2}{c^2} } }$
where v is the speed of the particle.

We want the total energy of the particle to be twice its rest energy, so that
$E=2E_0$
which means:
$\frac{m_0c^2}{ \sqrt{1- \frac{v^2}{c^2} } }=2m_0 c^2$
$\frac{1}{ \sqrt{1- \frac{v^2}{c^2} } }=2$
From which we find the ratio between the speed of the particle v and the speed of light c:
$\frac{v}{c}= \sqrt{1- (\frac{1}{2})^2 } =0.87$
So, the particle should travel at 0.87c in order to have its total energy equal to twice its rest energy.

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3 years ago

You have a source of energy containing 21 gj of energy at 600k how much this energy can be converted to work when rejecting heat

sweet [91]

Answer:

Available energy = 35 x 10⁶ J

Explanation:

Given:

Amount of energy (Q) = 21 gj = 21 x 10⁹ J

Temperature T1 = 600 k

Temperature T0 = 27 + 273 = 300k

Find:

Available energy

Computation:

Available energy = Q[1/T0 - 1/T1]

Available energy = 21 x 10⁹ J[1/300 - 1/600]

Available energy = 35 x 10⁶ J

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2 years ago

an athlete swims the distance from one end of a 50m pool to the other end in a time of 25 s what is The Athlete's average speed

vredina [299]

Answer:

2.5 N

because Average speed is equal to distance divided by time

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3 years ago

Which tool would you use to measure the amount of rainfall

mariarad [96]

A rain gauge! Hope this helps!

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3 years ago

Read 2 more answers