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3 years ago

11

Can someone please help me with science.

1 answer:

Pie3 years ago

7 0

Answer:

I think it is D or A

Explanation:

I have not done this in a long time, so sorry if wrong.

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A traveler pulls on a suitcase strap at an angle 36° above the horizontal. If of work are done by the strap while moving the sui

ollegr [7]

Answer:

The tension in the strap is 74.82 N.

Explanation:

Given that,

Angle between the horizontal and the suitcase is 36 degrees.

The distance traveled by the suitcase is 15 meters.

Let the work done by the suitcase is 908 J. We know that the work done in the vector form is given by :

$W=Fd\ \cos\theta\\\\908=F\times 15\times cos(36)\\\\F=74.82\ N$

So, the tension in the strap is 74.82 N. Hence, this is the required solution.

6 0

3 years ago

Identify the charge(s) with increasing electric potential energy.

kap26 [50]

Cznxjsjssbsishsisbsisbsisbsbeoeb

4 0

3 years ago

Two carts, one twice as heavy as the other, are at rest on a horizontal track. A person pushes each cart for 8 s. Ignoring frict

GalinKa [24]

Answer:

The correct option is: B that is 1/2 K

Explanation:

Given:

Two carts of different masses, same force were applied for same duration of time.

Mass of the lighter cart = $m$

Mass of the heavier cart = $2m$

We have to find the relationship between their kinetic energy:

Let the KE of cart having mass m be "K".

and KE of cart having mass m be "K1".

As it is given regarding Force and time so we have to bring in picture the concept of momentum Δp and find a relation with KE.

Numerical analysis.

⇒ $KE = \frac{mv^2}{2}$

⇒ $KE = \frac{mv^2}{2}\times \frac{m}{m}$

⇒ $KE = \frac{m^2v^2}{2}\times \frac{1}{m}$

⇒ $KE = \frac{(mv)^2}{2}\times \frac{1}{m}$

⇒ $KE = \frac{(\triangle p)^2}{2}\times \frac{1}{m}$

⇒ $KE = \frac{(\triangle p)^2}{2m}=\frac{(F\times t)^2}{2m}$

Now,

Kinetic energies and their ratios in terms of momentum or impulse.

KE (K) of mass m.

⇒ $K=\frac{(F\times t)^2}{2m}$ ...equation (i)

KE (K1) of mass 2m.

⇒ $K_1=\frac{(F\times t)^2}{2\times 2m}$

⇒ $K_1=\frac{(F\times t)^2}{4m}$ ...equation (ii)

Lets divide K1 and K to find the relationship between the two carts's KE.

⇒ $\frac{K_1}{K} =\frac{(F\times t)^2}{4m} \times \frac{2m}{(F\times t)^2}$

⇒ $\frac{K_1}{K} =\frac{2m}{4m}$

⇒ $\frac{K_1}{K} =\frac{2}{4}$

⇒ $\frac{K_1}{K} =\frac{1}{2}$

⇒ $K_1=\frac{K}{2}$

⇒ $K_1=\frac{1}{2}K$

The kinetic energy of the heavy cart after the push compared to the kinetic energy of the light cart is 1/2 K.

7 0

2 years ago

If a person has the genotype Rr for hair where red is dominant to blue, what phenotype would this person have?

JulijaS [17]

the person's phenotype would be red hair. phenotype is what you see on the outside, genotype is what the dna says. <3

4 0

2 years ago

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this

Afina-wow [57]

Answer: $27^{\circ}$

Explanation:

Given

Initial velocity of both snowball is 29.3 m/s

first snowball launch angle $=63^{\circ}$

Considering motion of snowball to be projectile

range is given by

$R=\frac{u^2\sin 2\theta }{g}$

$R=\frac{29.3^2\sin 126}{9.8}$

R=70.87 m-----1

If second snowball is thrown at an angle of \phi

$R=\frac{u^2\sin 2\phi }{g}$

$R=\frac{29.3^2\sin 2\phi }{9.8}$ ------2

$70.87=87.601\sin 2\phi$

$0.809=\sin \phi$

$2\phi can be 53.99^{\circ}$

or $180-2\phi =53.99^{\circ}$

Thus $\phi =26.995 \approx 27^{\circ}$

4 0

3 years ago