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kirza4 [7]
3 years ago
6

In a controlled experiment, the single factor manipulated by the researcher is

Chemistry
1 answer:
Georgia [21]3 years ago
6 0

Answer:

False

Explanation:

It is the opposite. A good way to remember is the that the dependent variable depends on the independent variable.

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The number of protons plus the number of neutrons in an atom is equal to its
sashaice [31]

Explanation:

mass number....................

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3 years ago
Which type of bond forms when two or more atoms share electrons?.
shepuryov [24]

Answer:

Covalent

Explanation:

Covalent is the sharing of electrons and Ionic is transferring of electrons.

7 0
2 years ago
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Find the standard enthalpy of formation of ethylene, C2H4(g), given the following data: C2H4(g) + 3 O2(g) --> 2CO2(g) + 2 H2O
Brums [2.3K]

Answer : The standard enthalpy of formation of ethylene is, 52.4 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of C_2H_4 will be,

2C(s)+2H_2(g)\rightarrow C_2H_4(g)    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)     \Delta H_1=-1411kJ

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-393.5kJ

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_3=-285.8kJ

Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equation, we get :

(1) 2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)     \Delta H_1=+1411kJ

(2) 2C(s)+2O_2(g)\rightarrow 2CO_2(g)    \Delta H_2=2\times (-393.5kJ)=-787kJ

(3) 2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)    \Delta H_3=2\times (-285.8kJ)=-571.6kJ

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+1411kJ)+(-787kJ)+(-571.6kJ)

\Delta H=52.4kJ

Therefore, the standard enthalpy of formation of ethylene is, 52.4 kJ

7 0
3 years ago
Which sentence best describes how scientists plan out their experiments?
malfutka [58]

Answer:

D

Explanation:

8 0
3 years ago
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A student prepares a solution of Potassium Nitrate (KNO3) containing 95g at 40 C. This solution is -
Sholpan [36]

Answer:

unsaturated

Explanation:

4 0
2 years ago
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