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kirza4 [7]
3 years ago
6

In a controlled experiment, the single factor manipulated by the researcher is

Chemistry
1 answer:
Georgia [21]3 years ago
6 0

Answer:

False

Explanation:

It is the opposite. A good way to remember is the that the dependent variable depends on the independent variable.

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Which subatomic particles are located in MOST of the space within an atom? A. protons B. neutrons C. electrons
IRISSAK [1]

Answer: -

C. Electrons

Explanation: -

Most of the space in an atom is empty. Through this space the electrons revolve around the centrally placed nucleus.

Inside the nucleus are present the protons and the neutrons. The nucleus size is very small compared to the rest of the atom.

Electrons carry negative charge, protons are positive and neutrons are neutral.

7 0
2 years ago
Most Bic lighters hold 5.0ml of liquified butane (density = 0.60 g/ml). Calculate the minimum size container you would need to "
Hatshy [7]

Answer:

Volume of container = 0.0012 m³ or 1.2 L or 1200 ml

Explanation:

Volume of butane = 5.0 ml

density = 0.60 g/ml

Room temperature (T) = 293.15 K

Normal pressure (P) = 1 atm = 101,325 pa

Ideal gas constant (R) = 8.3145 J/mole.K)

volume of container V = ?

Solution

To find out the volume of container we use ideal gas equation

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

First we find out number of moles

<em>As Mass = density × volume</em>

mass of butane = 0.60 g/ml ×5.0 ml

mass of butane = 3 g

now find out number of moles (n)

n = mass / molar mass

n = 3 g / 58.12 g/mol

n = 0.05 mol

Now put all values in ideal gas equation

<em>PV = nRt</em>

<em>V = nRT/P</em>

V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa

V = 121.87 ÷ 101,325 pa

V = 0.0012 m³ OR 1.2 L OR 1200 ml

8 0
3 years ago
73g of HCL in 2.00l of HCL solution
Whitepunk [10]
What is your question?
8 0
3 years ago
En un recipiente colocamos unos cubos de hielo luego tapamos y observamos que sucede despues de un tiempo
SSSSS [86.1K]

Three questions come along with the given statement. It is in Spanish language:



a) Por qué se humedeció la parte exterior del frasco?


b) Por qué el hielo disminuyó su volumen y ahora es agua?


c) Por qué puede haber agua en el exterior?



These are the three answers (in English).



First question:



a) Por qué se humedeció la parte exterior del frasco?



The question is Why did the outside of the bottle get wet?



Answer:



The outside of the bottle get wet because the ice cubes cooled the walls of the bottle, so the air surrounding the bottle also cooled.



The air contains humidity (water) in gas phase. The hotter the air the more the amount of humidity it can retain, the cooler the air the less the amount of humidity it can retain.


Then, when the air close to the walls of the bootle got cooler some of the water in the air became liquid and those are the drops of water that you see in the outside of the bottle.



Second question



b) Por qué el hielo disminuyó su volumen y ahora es agua?



The question is Why did the ice diminish its volume and now it is water?



Answer:




The ice diminished its volume and now it is water, becasue the ice, which is cooler than the surroundings, received heat energy (from the surroundings) and then its temperature increased. At some moment, this temperature reached the melting point of the ice (water) and it started to become liquid.



Third question



c) Por qué puede haber agua en el exterior?



The question is: Why can there be water outside?




Answer:



The water outside is outside since the beginning: it is in the air. You do not see it because it is gas state. When the air close to the walss of the bottle got cooler, part of the water in the air became liquid.

4 0
3 years ago
How many grams of oxygen gas (02) are needed to completely react with 9.30 moles
Luba_88 [7]

Answer:

223 g O₂

Explanation:

To find the mass of oxygen gas needed, you need to (1) convert moles Al to moles O₂ (via the mole-to-mole ratio from reaction coefficients) and then (2) convert moles O₂ to grams O₂ (via the molar mass). When writing your ratios/conversions, the desired unit should be in the numerator in order to allow for the cancellation of the previous unit. The final answer should have 3 sig figs because the given value (9.30 moles) has 3 sig figs.

4 Al + 3 O₂ ----> 2 Al₂O₃
^         ^

Molar Mass (O₂): 32.0 g/mol

9.3 moles Al          3 moles O₂              32.0 g
-------------------  x  ---------------------  x  --------------------  =  223 g O₂
                              4 moles Al               1 mole

6 0
2 years ago
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