Describe and explain one piece of evidence that a chemical reaction occurs when baking soda is added to vinegar

What other simple sugars have the same chemical formula as glucose?

Usimov [2.4K]

Answer:

The answer to your question is:

Explanation:

Other sugars with the same chemical formula as Glucose:

Sugar Formula Description

Glucose C₆H₁₂O₆ It's the most abundant monosaccharide.

Mannose C₆H₁₂O₆ It's found in plants and some animals.

Fructose C₆H₁₂O₆ It's the sugar of fruits.

Galactose C₆H₁₂O₆ It's found in milk.

8 0

3 years ago

An atom X has atomic number 15,it accepts 3 electrons in other to become stable,determine the,*Number of protons of the atom. *D

Lisa [10]

Answer:

15 protons

8 electrons in valence shell after accepting 3 electrons

Neutral/no charge before accepting 3 electrons

-3 charge after accepting 3 electrons

4 0

2 years ago

What kind of car do Cherry's and Marcia's boyfriends ride around in

Bond [772]

I believe it was a blue mustang

6 0

3 years ago

Which element will have the lower ionization energy? Be. Ba

sp2606 [1]

Boron would have the lower first ionization energy.
Be: 1s2 2s2
B: 1s2 2s2 2p1 -> electron from the p orbital is easier to eject than than electron from the s orbital.

6 0

3 years ago

Read 2 more answers

You are given a solid that is a mixture of Na2SO4 and K2SO4. A 0.205-g sample of the mixture is dissolved in water. An excess of

Svetach [21]

Answer:

Mass of SO₄⁻² = 0.123 g.

Mass percentage of SO₄⁻² = 41.2%

Mass of Na₂SO₄ = 0.0773 g

Mass of K₂SO₄ = 0.1277 g

Explanation:

Here we have

We place Na₂SO₄ = X and

K₂SO₄ = Y

Therefore

X +Y = 0.205 .........(1)

Therefore since the BaSO₄ is formed from BaCl₂, Na₂SO₄ and K₂SO₄ we have

Amount of BaSO₄ from Na₂SO₄ is therefore;

$X\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, Na_2SO_4}$

Amount of BaSO₄ from K₂SO₄ is;

$Y\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, K_2SO_4}$

Molar mass of

BaSO₄ = 233.38 g/mol

Na₂SO₄ = 142.04 g/mol

K₂SO₄ = 174.259 g/mol

$X\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, Na_2SO_4}$ = $X\times\frac{233.38 }{142.04}$ = 1.643·X

$Y\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, K_2SO_4}$ = $Y\times\frac{233.38 }{174.259 }$ = 1.339·Y

Therefore, we have

1.643·X + 1.339·Y = 0.298 g.....(2)

Solving equations (1) and (2) gives

The mass of SO₄⁻² in the sample is given by

Mass of sample = 0.298

Molar mass of BaSO₄ = 233.38 g/mol

Mass of Ba = 137.327 g/mol

∴ Mass of SO₄ = 233.38 g - 137.327 g = 96.05 g

Mass fraction of SO₄⁻² in BaSO₄ = 96.05 g/233.38 g = 0.412

Mass of SO₄⁻² in the sample is 0.412×0.298 = 0.123 g.

Percentage mass of SO₄⁻² = 41.2%

Solving equations (1) and (2) gives

X = 0.0773 g and Y = 0.1277 g.

8 0

3 years ago