Answer:
They will create an ionic bond.
Explanation:
The atom with the one valence electron will lose its one, because it's a metal and metals will lose electrons to become stable. The nonmetal (with 7 valence electrons) will gain that electron, therefore creating a stable octet for the nonmetal, making the compound stable.
H2O is classified as water.
Hope this helps! God bless
-vf
Answer:
1.38*10^4 L or 0.138*10^2 m^3
Explanation:
The balanced equation for the reaction is:
⇒ ![2NH_{3(g)}](https://tex.z-dn.net/?f=2NH_%7B3%28g%29%7D)
In the chemical equation above, 3 moles of hydrogen gas react with 1 mole of nitrogen gas to produce 2 moles of ammonia gas. A STP, 1 mole of gas is equivalent to 22.4 L. Therefore,
6.9 m^3 of nitrogen gas will be equivalent to 6900 L. In addition, 6900L will be equivalent to 6900/22.4 = 308.036 moles
1 mole of nitrogen produced 2 moles of ammonia gas, therefore, 308.04 moles of nitrogen gas would produce 2*308.036 moles = 616.07 moles of ammonia gas
At STP, 1 mole of gas is equivalent to 22.4 L, thus 616.07 moles will be equivalent to 22.4*616.07 = 13800 L or 13.8 m^3
At the same temperature, steam burns are often more severe that water burns because of water's high HEAT OF VAPORIZATION.
Water possesses high heat of vaporization. The heat of vaporization refers to the amount of heat that is needed to convert a unit mass of water to gas. After getting to the boiling point, a lot of heat is still needed to be absorbed by a boiling water before it can be converted to the gaseous form. Thus, the heat that is inherent in the steam is greater than that which is found in the boiling water, that is why the steam causes more damages.
Answer:
7.75 Calories per gram of candy
Explanation:
The equation of a calorimeter is:
Q = C×ΔT
Where Q is heat involved in the reaction, C is heat capacity of the calorimeter (46.80kJ K⁻¹) and ΔT is change in temperature (2.91°C). Replacing:
Q = 46.80kJ K⁻¹ ₓ 2.91K
Q = 136.2 kJ are produced. If 4.184 kJ = 1kCal:
136.2 kJ ₓ (1kCal / 4.184 kJ) = <em>32.55 kCal per 4.20g of candy. </em>Thus, Calories / g of candy are:
32.55 kCal / 4.20g = <em>7.75 Calories per gram of candy</em>