I hope this helps you
slope = -1 x'= -3 y'=5
slope. (x'-x)=y'-y
-1. (-3-x)=5-y
3+x=5-y
y=2-x
The answer is Hx = ½ Wsin θ cos θ
The explanation for this is:
Analyzing the torques on the bar, with the hinge at the axis of rotation, the formula would be: ∑T = LT – (L/2 sin θ) W = 0
So, T = 1/2 W sin θ. Analyzing the force on the bar, we have: ∑fx = Hx – T cos θ = 0Then put T into the equation, we get:∑T = LT – (L/2 sin θ) W = 0
Answer:
4
Step-by-step explanation:
