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Svetllana [295]
3 years ago
10

Determine the grams of water produced when 250 grams of barium hydroxide react

Chemistry
1 answer:
Mrac [35]3 years ago
8 0

Answer:

Explanation:

Ba(OH)₂ (aq) + 2HCl (aq) --> 2H₂O (l) + BaCl₂ (aq)

171 g                    2 x 36.5 g     2 x 18 g

73 g of HCl reacts with 171 g of Ba(OH)₂

125 g HCl reacts with 171 x 125 / 73 g of Ba(OH)₂

= 292.8 g of  of Ba(OH)₂

Ba(OH)₂  available is 250 g , so it is the limiting reagent .

171 g of Ba(OH)₂ forms 36 g of water

250 g of Ba(OH)₂ forms 36 x 250 / 171 g of water

= 52.63 g of water.

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