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kvv77 [185]
2 years ago
12

A scientist has 500 mL of a 2.1 M stock solution. She dilutes the solution, and the volume of the solution after the dilution is

3.25 L. What is the molarity (M) of the diluted solution?
Chemistry
1 answer:
Liono4ka [1.6K]2 years ago
4 0

The molarity of the diluted solution is 0.32 M

Considering the question given above, the following data were obtained:

Volume of stock solution (V₁) = 500 mL

Molarity of stock solution (M₁) = 2.1 M

Volume of diluted solution (V₂) = 3.25 L = 3.25 × 1000 = 3250 mL

<h3>Molarity of diluted solution (M₂) =....? </h3>

The molarity of the diluted solution can be obtained as follow:

<h3>M₁V₁ = M₂V₂</h3>

2.1 × 500 = M₂ × 3250

1050 = M₂ × 3250

<h3>Divide both side by 3250</h3><h3 />

M₂ = 1050 / 3250

<h3>M₂ = 0.32 M</h3>

Therefore, the molarity of the diluted solution is 0.32 M

Learn more: brainly.com/question/22325751

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For the reaction 2Fe + O2 = 2FeO, how many grams of iron oxide are produced from 8.00 mol of iron? when o2 is an excess
Yanka [14]

Answer:

The answer to your question is 576 grams of FeO

Explanation:

Balanced chemical reaction

                      2Fe  +  O₂  ⇒  2 FeO

       Reactant             Elements         Products

             2                         Fe                     2

             2                         O                       2

Data

mass of FeO = ?

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Process

1.- Convert moles of Fe to grams

Atomic mass = 56 g

                         56 g of Fe ------------------ 1 mol

                           x               ------------------ 8 moles

                           x = (8 x 56) / 1

                           x = 448 g of Fe

2.- Use the coefficients of the balanced reaction to find the grams of FeO.

Molecular mass of FeO = 2[ 56 + 16]

                                       = 144 g

               2(56) g of Fe ----------------------- 144 g of FeO

               448 g             -----------------------  x

                x = (448 x 144) / 2(56)

                x = 64512 / 112

               x = 576 grams of FeO

                       

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Treatment of 2,4,6-tri-tert-butylphenol with bromine in cold acetic acid gives the compound C18H29BrO in quantitative yield. The
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1. Information from the formulas

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2. Information from the reaction

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(i) The bromonium ion attacks at the para position, forming a resonance-stabilized carbocation intermediate.

(ii) A bromide ion attacks the H of the hydroxyl group to form 2,4,6-tri-tert-butylcyclohexa-2,5-dienone.

4. Confirmatory evidence (Fig. 2)

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(b)NMR

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