Answer:
222.2N/m
Explanation:
Given parameters:
Elastic potential energy = 4000J
Extension = 6m
Unknown:
Spring coefficient = ?
Solution:
The elastic potential energy is the energy stored within a string.
It is expressed as;
EPE =
k e²
k is the spring constant
e is the extension
4000 =
x k x 6²
8000 = 36k
k = 222.2N/m
Well the wife one is to be able to handle the nail and the sharp part is to put it in side of something like a wall
Answer:
the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°
Explanation:
Given the data in the question and as illustrated in the diagram below.
speed of the ship v = 0.90c
base of the ladder from the wall x₀ = 3.0 m
top of the later above the floor y = 4.0 m
we determine angle θ.
from the diagram,
tanθ = y/x₀
tanθ = y / x₀√( 1 - v²/c² )
we substitute
tanθ = 4.0 / 3.0√( 1 - ((0.9c)²/c²) )
tanθ = 4.0 / 3.0√( 1 - ((0.9²)c²/c²) )
tanθ = 4.0 / 3.0√( 1 - (0.9²) )
tanθ = 4.0 / 3.0√( 1 - 0.81 )
tanθ = 4.0 / 3.0√0.19
tanθ = 4.0 / 1.30766968
tanθ = 3.058876
θ = tan⁻¹( 3.058876 )
θ = 71.8965 ≈ 71.9°
Therefore, the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°
Answer:
r=2.6 cm
Explanation:
Hi!
Lets call steel material 1, and the new alloy material 2. You know their densities:

The volume of a sphere with radius r is given by:
Then the masses of the bearings are:

For the masses to be the same:
![\rho_1 V_1 = \rho_2 V_2\\\frac{V_2}{V_1} =\frac{\rho_1}{\rho_2}\\(\frac{r_2}{r_1})^3 = \frac{8.08}{3.14}=2.57\\r_2=\sqrt[3]{2.57}\;r1 =1.37r_1=1.37*1.9cm=2.6cm](https://tex.z-dn.net/?f=%5Crho_1%20V_1%20%3D%20%5Crho_2%20V_2%5C%5C%5Cfrac%7BV_2%7D%7BV_1%7D%20%3D%5Cfrac%7B%5Crho_1%7D%7B%5Crho_2%7D%5C%5C%28%5Cfrac%7Br_2%7D%7Br_1%7D%29%5E3%20%3D%20%5Cfrac%7B8.08%7D%7B3.14%7D%3D2.57%5C%5Cr_2%3D%5Csqrt%5B3%5D%7B2.57%7D%5C%3Br1%20%3D1.37r_1%3D1.37%2A1.9cm%3D2.6cm)