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xenn [34]
3 years ago
11

Please help I will mark you brainliest

Physics
2 answers:
Radda [10]3 years ago
7 0

I believe the answer is a

NISA [10]3 years ago
7 0
The correct answer is D, that is the point of the lowest elevation on the map.
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Help please I’ll mark as brainliest
kirza4 [7]

Answer:

yes

Explanation:

6 0
3 years ago
What is the spring coefficient of a spring that stores 4000 joules of energy
Verizon [17]

Answer:

222.2N/m

Explanation:

Given parameters:

Elastic potential energy = 4000J

Extension  = 6m

Unknown:

Spring coefficient  = ?

Solution:

The elastic potential energy is the energy stored within a string.

It is expressed as;

           EPE = \frac{1}{2} k e²  

k is the spring constant

e is the extension

         4000  =  \frac{1}{2} x k x 6²  

        8000  =  36k

          k  = 222.2N/m

6 0
3 years ago
Why does one end of a nail is wide while the other end is sharp?​
spayn [35]
Well the wife one is to be able to handle the nail and the sharp part is to put it in side of something like a wall
5 0
3 years ago
Read 2 more answers
A ladder 5.0 m long leans against a wall inside a spaceship. From the point of view of a person on the ship, the base of the lad
andriy [413]

Answer:

the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

Explanation:

Given the data in the question and as illustrated in the diagram below.

speed of the ship v = 0.90c

base of the ladder from the wall x₀ = 3.0 m

top of the later above the floor y = 4.0 m

we determine angle θ.

from the diagram,

tanθ = y/x₀

tanθ = y / x₀√( 1 - v²/c² )

we substitute

tanθ = 4.0 / 3.0√( 1 - ((0.9c)²/c²) )

tanθ = 4.0 / 3.0√( 1 - ((0.9²)c²/c²) )

tanθ = 4.0 / 3.0√( 1 - (0.9²) )

tanθ = 4.0 / 3.0√( 1 - 0.81 )

tanθ = 4.0 / 3.0√0.19

tanθ = 4.0 / 1.30766968

tanθ = 3.058876

θ = tan⁻¹( 3.058876 )

θ = 71.8965 ≈ 71.9°

Therefore, the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

3 0
3 years ago
You have been working on a new, strong, lightweight ceramic which will be used to replace steel bearing balls. One cubic meter o
marin [14]

Answer:

r=2.6 cm

Explanation:

Hi!

Lets call steel material 1, and the new alloy material 2. You know their densities:

\rho_1=8.08*10^3\frac{kq}{m^3}\\\rho_2=3.14*10^3\frac{kq}{m^3}

The volume of a sphere with radius r is given by:

V=\frac{4}{3}\pi r^3

Then the masses of the bearings are:

m_1=\rho_1V_1=\frac{4}{3}\pi r_1^3 \\m_1=\rho_2V_2=\frac{4}{3}\pi r_2^3

For the masses to be the same:

\rho_1 V_1 = \rho_2 V_2\\\frac{V_2}{V_1} =\frac{\rho_1}{\rho_2}\\(\frac{r_2}{r_1})^3 = \frac{8.08}{3.14}=2.57\\r_2=\sqrt[3]{2.57}\;r1 =1.37r_1=1.37*1.9cm=2.6cm

5 0
4 years ago
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