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3 years ago

15

What will happen if you drop a golf ball, a baseball, and a bowling ball at the same instant from the top of a tall building

1 answer:

V125BC [204]3 years ago

8 0

Depending on the height of the building they can break due to impact on the floor.

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A proposed ocean thermal-energy conversion (OTEC) system is a heat engine that would operate between warm water (16°C) at the oc

LenaWriter [7]

Answer:

$3.46$ %

Explanation:

We have given cooler temperature that is $T_c$ = 6°C =273+6=279 K

And the warm temperature of water that is $T_h=16^{\circ}C=16+273=289\ K$

The maximum possible efficiency is given by $\eta =1-\frac{T_c}{T_h}$

So maximum efficiency $\eta =1-\frac{T_c}{T_h}=1-\frac{279}{289}=0.0346=3.46$ %

6 0

3 years ago

A fine-grained sedimentary rock is known as _____.

Yakvenalex [24]

The finer‐grained<span> s</span>edimentary rocks<span> are called shale, siltstone, and mudstone</span>

5 0

3 years ago

What is the collective noun of chocolate

Vedmedyk [2.9K]

Answer:

creamy with milk and chocolate

4 0

3 years ago

A diver running 2.5 m/s dives out horizontally from the edge of a vertical cliff and 3.0 s later reaches the water below. how hi

Elodia [21]

<u>Answer:</u>

a) Height of cliff = 44.145 meter

b) 7.5 meter far from its base the diver hit the water.

<u>Explanation:</u>

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Diver's vertical motion:

Initial velocity = 0 m/s, acceleration = 9.8 $m/s^2$ , we need to calculate displacement when time is 3 seconds.

$s= ut+\frac{1}{2} at^2\\ \\ =0*3+\frac{1}{2} *9.81*3^2\\ \\ =44.145meter$

So height of cliff = 44.145 meter.

b) Diver's horizontal motion:

Initial velocity = 2.5 m/s, acceleration = 0 $m/s^2$ , we need to calculate displacement when time is 3 seconds.

$s= 2.5*3+\frac{1}{2}*0*3^2\\ \\ =7.5meter$

So 7.5 meter far from its base the diver hit the water.

5 0

3 years ago

You are driving to the grocery store at 20 m/s. You are 110m from an intersection when the traffic light turns red. Assume that

oksano4ka [1.4K]

As we know that reaction time will be

$t = 0.50 s$

so the distance moved by car in reaction time

$d = vt$

$d = 20 \times 0.50$

$d = 10 m$

now the distance remain after that from intersection point is given by

$d = 110 - 10 = 100 m$

So our distance from the intersection will be 100 m when we apply brakes

now this distance should be covered till the car will stop

so here we will have

$v_f = 0$

$v_i = 20 m/s$

now from kinematics equation we will have

$v_f^2 - v_i^2 = 2 a d$

$0 - 20^2 = 2(a)100$

$a = \frac{-400}{200} = -2 m/s^2$

so the acceleration required by brakes is -2 m/s/s

Now total time taken to stop the car after applying brakes will be given as

$v_f - v_i = at$

$0 - 20 = -2 (t)$

$t = 10 s$

total time to stop the car is given as

$T = 10 s + 0.5 s = 10.5 s$

3 0

3 years ago