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mariarad [96]
3 years ago
15

What will happen if you drop a golf ball, a baseball, and a bowling ball at the same instant from the top of a tall building

Physics
1 answer:
V125BC [204]3 years ago
8 0
Depending on the height of the building they can break due to impact on the floor.
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a helium ballon containing 5m³ of gas at a pressure of 30kPa is released into the air. Assuming that the temperature is constant
IRISSAK [1]

Answer:

345m3

Explanation:

4 0
3 years ago
A flowerpot falls from the ledge of an apartment building. A person in an apartment below, coincidentally holding a stopwatch, n
valkas [14]

Answer

given,

height of window = 4 m

time taken to travel = 1 s

acceleration due to gravity = 9.8 m/s²

s = ut + \dfrac{1}{2}at^2

u = \dfrac{s - \dfrac{1}{2}at^2}{t}

u = \dfrac{4 - \dfrac{1}{2}\times 9.8\times 1^2}{1}

u = -0.905 m/s

initial velocity of ledge v = 0

now,

v² = u² + 2 a s

(-0.905)² = 0 + 2 × 9.8 ×s

s = 0.042 m

6 0
3 years ago
you push a 51 kg box with a force of 485 N. the friction force on the box is 232 N. calculate the acceleration of the crate.
vichka [17]

Answer:

a = 4.96 m/s²

Explanation:

Given,

The mass of the box, m = 51 Kg

The magnitude of the applied force, Fₐ = 485 N

The friction force on the box, Fₓ = 232 N

The net force acting on the box is,

                                 F = Fₐ - Fₓ

Substituting the given values in the above equation

                                  F = 485 - 232

                                    = 253 N

The acceleration of the crate is given by

                                   a = F/m

                                      = 253 / 51

                                      = 4.96 m/s²

Hence, the acceleration of the crate is, a = 4.96 m/s²

3 0
3 years ago
A 61.0-kg person jumps from rest off a 10.0-m-high tower straight down into the water. Neglect air resistance. She comes to rest
9966 [12]

Answer:

Explanation:

In this case, law of conservation of energy will be implemented. It states that "the energy of the system remains conserved until or unless some external force act on it. Energy of the system may went through the conversion process like kinetic energy into potential and potential into kinetic energy.But their total always remain the same in conserved systems."

Given data:

Height of tower = 10.0 m

Depth of the pool = 3.00 cm

Mass of person = 61.0 kg

Solution:

Initial energy = Final energy

U_{i} =  (K.E) + U_{f}

As the person was at height initially so it has the potential energy only.

mg(h_{1} +h_{2}) = K.E + mgh_{2}

K.E = mgh_{1}

K.E = (61.0)(9.8)(10)\\K.E = 5978 J

Lets find out the magnitude of the force that the water is exerting on the diver.

W =ΔK.E

F.h_{2} = 5978\\

F = \frac{5978}{3}

F = 1992.67 N

7 0
3 years ago
A 900-kg car traveling east at 15.0 m/s collides with a 750-kg car traveling west at 20.0 m/s. The cars stick together. What is
andriy [413]

Answer:

17.27m/s

Explanation:

M1U1 + M2U2 = (M1+M2)V

(900x15) + (750 x 20) = (900+750)V

13500+15000 = (1650)V

28500 = 1650v

V = 28500/1650 = 17.27m/s

V = 17.27m/s

5 0
3 years ago
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