What is the key element fountain all carbohydrates lipids proteins and nucleus acid

The ideal gas constant, R has several different values that could be used. Which quantity causes these differences? pressure tem

Blababa [14]

Answer : The correct option is, pressure.

Explanation :

The ideal gas equation is,

$PV=nRT$

where,

P = pressure of the gas

V = volume of the gas

n = number of moles of gas

T = temperature of the gas

R = gas constant

The value of 'R' has several different values which are :

$R=0.08205L.atm/mol.K$

$R=8.3145L.kPa/mol.K$

$R=8.3145J/mol.K$

$R=1.987cal/mol.K$

$R=0.08314L.bar/mol.K$

That means, the value of 'R' is different due the change in the pressure value and all the variables (temperature, volume and moles) are constant.

Hence, the correct option is, pressure.

3 0

3 years ago

Which of the following is true of carbon?

pashok25 [27]

I’m pretty sure it’s A or C

8 0

3 years ago

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Which 3 elements had complete out shells? (you will probably need to use the periodic table)

wlad13 [49]

The inert gases like neon,argon ,krypton have complete shells

3 0

3 years ago

A compound is found to contain 37.32 % phosphorus , 16.88 % nitrogen , and 45.79 % fluorine by

Alla [95]

Answer: 1. The empirical formula is $PNF_2$

2. The molecular formula is $PNF_2$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of P = 37.32 g

Mass of N = 16.88 g

Mass of F = 45.79 g

Step 1 : convert given masses into moles.

Moles of P = $\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{37.32g}{31g/mole}=1.20moles$

Moles of N = $\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.88g}{14g/mole}=1.20moles$

Moles of F = $\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{45.79g}{19g/mole}=2.41moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For P = $\frac{1.20}{1.20}=1$

For N = $\frac{1.20}{1.20}=1$

For F = $\frac{2.41}{1.20}=2$

The ratio of P: N: F= 1: 1: 2

Hence the empirical formula is $PNF_2$

The empirical weight of $PNF_2$ = 1(31)+1(14)+2(19)= 82.98 g.

The molecular weight = 82.98 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{82.98}{82.98}=1$

The molecular formula will be= $1\times PNF_2=PNF_2$

3 0

3 years ago

Calculate the number of moles equivalent to 12.7 gram of iodine molecule

Alexus [3.1K]

$\LARGE{ \boxed{ \purple{ \rm{Answer}}}}$

☃️ Chemical formulae ➝ $\sf{I_2}$

How to find?

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

$\boxed{ \sf{No. \: of \: moles = \frac{Given \: weight}{Molecular \: weight} }}$

Solution:

❍ Molecular weight of $\sf{I_2}$

= 2 × 126.90

= 253.80

= 254 (approx.)

❍ Given weight: 12.7

Then, no. of moles,

⇛ No. of moles = 12.7 / 254

⇛ No. of moles = 0.05 moles

⚘ No. of moles of Iodine molecule in the given weight = 0.05 moles

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6 0

3 years ago

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