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MrRa [10]
3 years ago
9

Autobus porusza się ze stałą prędkością 54 km/h Oblicz w jakim czasie przebędzie drogę 450 m

Physics
1 answer:
maria [59]3 years ago
3 0

Answer:

Autobus porusza się ze stałą prędkością 54 km/h Oblicz w jakim czasie przebędzie drogę 450 m

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Why the weight of the body varries from place to place on the earth's surface ​
Scorpion4ik [409]

Answer:

mass of the body is constant as it is property of body, but weight is product of acceleration due to gravity and mass, which may vary from place to place because acceleration due to gravity is different for different places.

5 0
3 years ago
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The​ time, t, required to drive a fixed distance varies inversely as the​ speed, r. It takes 3 hr at a speed of 14 ​km/h to driv
kenny6666 [7]

Answer:

time taken with speed 23 km/h will be 1.8 hours or 1 hour 48 minutes

Explanation:

Given:

Time is inversely proportional to the speed

mathematically,

t ∝ (1/r)

let the proportionality constant be 'k'

thus,

t = k/r

therefore, for case 1

time = 3 hr

speed = 14 km/hr

3 = k/14

also,

for case 2

let the time be = t

r = 23 km/h

thus,

we have

t = k/23

on dividing equation 2 by 1

we get

\frac{t}{3}=\frac{k/23}{k/14}

or

t=\frac{14\times3}{23}

or

t = 1.8 hr = or 1 hour 48 minutes ( 0.8 hours × 60 minutes/hour = 48 minutes)

4 0
3 years ago
What is the difference in electrical potential energy between two places in an electric field?
Phoenix [80]

Answer: Option (c) is the correct answer.

Explanation:

The difference in electrical potential energy between two places in an electric field is known as potential difference.

Mathematically, potential difference between two given points can be written as follows.

             \Delta V = V_{2} - V_{1}

where,    \Delta V = potential difference

              V_{1} = potential at point 1

               V_{1} = potential at point 2

                         

4 0
3 years ago
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Calculate the force it would take to accelerate a 650-kg vehicle at a rate of 3 m/s^2
aleksklad [387]

Explanation:

Newton's second law:

F = ma

F = (650 kg) (3 m/s²)

F = 1950 N

3 0
4 years ago
A playground merry-go-round of radius 2.00 m has a moment of inertia I = 275 kg · m2 and is rotating about a frictionless vertic
ryzh [129]

Answer:

0.2932 rad/s

Explanation:

r = Radius = 2 m

I_i = Initial angular momentum = 275\ kgm^2

\omega_i = Initial angular velocity = 14 rev/min

I_f = Final angular momentum

\omega_f = Final angular velocity

Here the angular momentum of the system is conserved

I_i\omega_i=I_f\omega_f\\\Rightarrow 275\times 14\times \dfrac{2\pi}{60}=(275+275(2)^2)\omega_f\\\Rightarrow \omega_f=\dfrac{275\times 14\times \dfrac{2\pi}{60}}{275+275(2)^2}\\\Rightarrow \omega_f=0.2932\ rad/s

The final angular velocity is 0.2932 rad/s

7 0
3 years ago
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