Explanation:
see the above attachment to solve the question and get the answer.
hope this helps you.
Answer:
distance between object and image = 18.9 cm
Explanation:
given data
radius of curvature = 18 cm
focal length = 1/2 radius of curvature
magnification = 40%
to find out
distance between object and image
solution
we know lens formula that is
1/f = 1/v + 1/u ....................1
here f = 18 /2 and v and u is object and image distance
and we know m = 40% = 0.40
so 0.40 = -v / u
so here v = - 0.40 u
so from equation 1
1/f = 1/v + 1/u
2/18 = - 1/0.40u + 1/u
u = -13.5 cm ..................2
and
v = -0.40 (- 13.5)
v = 5.4 cm ......................3
so from equation 2 and 3
distance between object and image = 5.4 + 13.5
distance between object and image = 18.9 cm
A. Getting a full set of valence electrons
Explanation:
The best description of the end result of chemical bonding for most atoms is the getting of a full set of valence electrons.
Atoms reacts with one another in order to complete valence electronic shell.
- The valence electron shell is the outermost energy level of an atom.
- It is from this energy level that electrons are lost or gained to form bonds.
- All atoms wants to be like the noble gases whose valence electronic shell is completely filled up
- This is the crux of chemical bonding
- The attraction that is produced from the interaction leads to bond formation
learn more:
Chemical bond brainly.com/question/10903097
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Gravity causes a falling object to fall 9.8 m/s faster every second it falls.
Kenny's book started out with no speed when it was dropped.
1.5 sec later, it was falling at (9.8 x 1.5) = 14.7 m/s .
During the fall, its average speed was 1/2(0 + 14.7) = 7.35 m/s .
Distance it covered = (average speed) x (time) =
(7.35 m/s) x (1.5 sec) = 11.025 m
