Answer:
d. The earth rotates around the sun
Explanation:
- Nicolas Copernicus is considered the first person to give the theory of heliocentric, or Sun-centered system of our planetary system.
- In the heliocentric system, it is considered that the sun is stationary and the earth revolves around the sun.
- He stated that the sun is at the center of the universe and the earth spins on its axis once daily and revolves around the sun in one year.
- And today we know it is correct that earth rotates on its own axis and also revolves around the sun.
Answer:
charges of the beads is 1.173 ×
C
Explanation:
given data
mass = 3.8589 g = 0.003859 kg
spring length = 5 cm = 0.05 m
extend spring x = 1.5747 cm = 0.15747 m
spring's extension = 0.0116 m
to find out
charges of the beads
solution
we know that force is
force = mass × g
force = 0.003859 × 9.8
force = 0.03782 N
so we know force for mass
force = -kx
so k = force / x
put here force and x value
k = -0.03782 / 0.1575
k = -0.24 N/m
and
force for spring's extension
force = -kx
force = -0.24 ( 0.0116) = 0.002784 N
so here
total length L = 0.05 + 0.0116 = 0.0616
so charges of the beads = force × L² / ke
charges of the beads = 0.002784 × (0.0616)² / (9 ×
)
so charges of the beads = 1.173 × C
Hi!
The answer is <span>B. Language influences how people understand their world.
Hope this helps!
-Payshence xoxo</span>
(a) The work done by the force applied by the tractor is 79,968.47 J.
(b) The work done by the frictional force on the tractor is 55,977.93 J.
(c) The total work done by all the forces is 23,990.54 J.
<h3>
Work done by the applied force</h3>
The work done by the force applied by the tractor is calculated as follows;
W = Fd cosθ
W = (5000 x 20) x cos(36.9)
W = 79,968.47 J
<h3>Work done by frictional force</h3>
W = Ffd cosθ
W = (3500 x 20) x cos(36.9)
W = 55,977.93 J
<h3>Net work done by all the forces on the tractor</h3>
W(net) = work done by applied force - work done by friction force
W(net) = 79,968.47 J - 55,977.93 J
W(net) = 23,990.54 J
Learn more about work done here: brainly.com/question/25573309
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Answer:
F₄ = 29.819 N
Explanation:
Given
F₁ = (- 25*Cos 50° i + 25*Sin 50° j + 0 k) N
F₂ = (12*Cos 50° i + 12*Sin 50° j + 0 k) N
F₃ = (0 i + 0 j + 4 k) N
Then we have
F₁ + F₂ + F₃ + F₄ = 0
⇒ F₄ = - (F₁ + F₂ + F₃)
⇒ F₄ = - ((- 25*Cos 50° i + 25*Sin 50° j) N + (12*Cos 50° i + 12*Sin 50° j) N + (4 k) N) = (13*Cos 50° i - 37*Sin 50° j - 4 k) N
The magnitude of the force will be
F₄ = √((13*Cos 50°)² + (- 37*Sin 50°)² + (- 4)²) N = 29.819 N
