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2 years ago

1. A fossil is the remains or traces of organisms that lived in the past.

Chemistry

1 answer:

algol132 years ago

4 0

Answer:

Is this from edge?

if so which lesson is it from and is this an assignment or a quiz?

I think the answer is C (Much of the evidence for evolution comes from fossils.)

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Determine the freezing point depression of 2 kg of water when 2 mol salt is added to it. The kf of water is 1.86 degrees C/M. Sh

Svet_ta [14]

Answer: The freezing point depression is $1.86^0C$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=K_f\times m$

$\Delta T_f$ = Depression in freezing point

$K_f$ = freezing point constant = $1.86^0C/m$

m= molality = $\frac{\text {moles of solute}}{\text {mass of solvent in kg}}=\frac{2mol}{2kg}=1m$

$\Delta T_f=1.86mol/kg^0C\times 1m$

$\Delta T_f=1.86^0C$

Thus freezing point depression is $1.86^0C$

3 0

2 years ago

A chemist has two large containers of sulfuric acid solution, with different concentrations of acid in each container. Blending

vitfil [10]

Answer:

0.015% and 0.012%

Explanation:

using simultaneous equation

6 0

3 years ago

Red aesthetic and one other thing

Katena32 [7]

I was on the phone to see if you wanted me a couple questions and I would be able answer questions on how

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2 years ago

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Convert this molecular formula into a structure that is consistent with the usual bonding patterns. C2h6o if more than one struc

Eddi Din [679]

The given formula contains two carbon along with six hydrogen and an oxygen.

The possible isomers from $C_2H_6O$ are ethanol and dimethyl ether.

Ehtanol is an alcohol containing a hydroxyl group whereas dimethyl ether is an ether containing an oxygen between two methyl

The structure of two isomers are:

8 0

3 years ago

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A standard solution contained 0.8 mg/mL. A student took 2 mL of the standard solution and added 10 mL of water. What is the new/

galben [10]

To get the concentration of the second solution let us use the following formulae

C1V1=C2V2 where C1 is concentration of first solution and V1 is the volume of solution first solution. on the other hand C2 is the concentration of second solution and V2 is the volume of second solution.

therefore

0.8×2=(2+10)×C2
1.6 =12×C2
1.6/12=C2
C2 = 0.1333mg/mL

7 0

3 years ago

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