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3 years ago

In a redox reaction, one of the reactants must release

1 answer:

3 0

Redox reaction is the reduction and oxidation reaction. It is a chemical reaction that involves a transfer of electrons. It can mean loss of oxygen (oxidation) or gain of electrons (reduction). Oxydation is the process of where a sustance loses electrons, gains an oxygen atom/s, loses a hydrogen atom/s. reduction is the opposite.
In a redox reaction, one of the reactants must release electrons.

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In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to

labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of $NH_3$ = 100 g

Molar mass of $NH_3$ = 27 g/mole

Molar mass of $N_2$ = 28 g/mole

First we have to calculate moles of $NH_3$ .

$\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles$

The given balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the given reaction, we conclude that

2 moles of $NH_3$ produced from 1 mole of $N_2$

3.7 moles of $NH_3$ produced from $\frac{1mole}{2mole}\times 3.7mole=1.85moles$ of $N_2$

Now we have to calculate the mass of $N_2$ .

Mass of $N_2$ = Moles of $N_2$ × Molar mass of $N_2$

Mass of $N_2$ = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

5 0

3 years ago

Find the work done using data from the PV plot for an isothermal system.

Eduardwww [97]

Answer:

W = - 500 KJ

∴ the work is done on the system

Explanation:

isothermal system:

∴ ΔU = 0; ⇒ Q = W

∴ W = P1V1 -P2V2

⇒ W = ((100KPa)*(25m³)) - ((300KPa)*(10m³))

⇒ W = 2500KPa.m³ - 3000KPa,m³

⇒ W = - 500 KPa.m³ = - 500 KJ

∴ W (-) the work is done on the system

8 0

3 years ago

The unknown ionic compound gave a red flame test, NR with ammonium carbonate, and a red/orange halide test. What is the unknown

harkovskaia [24]

Answer:

This question is incomplete, however, the unknown compound can be inferred to be "Lithium Bromide"

Explanation:

The unknown compound firstly is said to be an ionic compound. An ionic/electrovalent compound is a compound in which it's constituent ions transfer/receive electron(s). They are mostly made of group 1 and group 7 elements. Examples include NaCl, NaF, LiF and KCl.

Also, the ion (metallic ion) that produces a red flame test colour in a flame test is the Lithium ion (Li⁺). Also, when dissolved in water or hexane, the only halogen that produces a red/orange colour is bromine. Hence, the unknown ionic compound can be inferred to be Lithium Bromide.

5 0

3 years ago

Which of the following best summarizes the ideal gas law?

8090 [49]

Answer:

Option C. PV = nRT

Explanation:

The ideal gas gas equation gives the relationship between pressure, volume, number mole a gas and temperature of gas.

Mathematically, the ideal gas equation is given as:

PV = nRT

Where:

P is the pressure measured in atmosphere (atm).

V is the volume measured in litres(L) or cubic decimetre (dm³).

n is the number of mole of gas.

R is the gas constant (0.0821atm.L/Kmol)

T is temperature measured in Kelvin (K).

4 0

3 years ago

Sodium borohydride, NaBH4, and boron trifluoride, BF3, are compounds of boron. What are the shapes around boron in the borohydri

STatiana [176]

Compound 1: Sodium borohydride
In sodium borohydride (NaBH4), B is a central metal.
Electronic configuration of B is 1s2 2s2 2p1.
B undergoes sp3 hybridization in NaBH4, to generate 4 hybrid orbitals. These hybrid orbitals, forms sigma bond with 4 'H' atoms. Due to this, the structure of sodium borohydride in tetrahedral.
........................................................................................................................

Compound 2: Boron trifluoride
In boron trifluoride (BF3), B is a central metal.
Electronic configuration of B is 1s2 2s2 2p1.
B undergoes sp2 hybridization in NaBH4, to generate 3 hybrid orbitals. These hybrid orbitals, forms sigma bond with 3 'H' atoms. Due to this, the structure of boron trifluoride is triangular planner.

7 0

3 years ago

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