Food consumption affects the rate of alcohol absorption in the bloodstream.
Explanation:
The type of food and therefore the amount<span> of food that </span>is a gift<span> in your </span>epithelial duct once you<span> consume alcohol have </span>the foremost<span> direct </span>impact<span> on </span>the speed<span> of alcohol absorption.</span>
<span>When you consume alcohol on </span>the associate<span> empty </span>abdomen<span>, the alcohol </span>is sometimes<span> absorbed </span>within the<span> blood </span>among<span> fifteen minutes to two-and-a-half hours. If </span>you have got<span> a moderate </span>quantity<span> of food in your </span>abdomen once you<span> drink, that speed slows </span>all the way down to<span> thirty minutes </span>to a few<span> hours. If you’re drinking on a full </span>abdomen<span>, alcohol absorption ranges from </span>3 to 6<span> hours.</span>
Principal Energy Light Type of sub level Maximum number of electrons
P 8
2
S 18
3
P
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Complete question:
The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.
If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?
Answer:
After 210 s the concentration of SO2Cl2 will be 0.121 M
Explanation:
![ln\frac{[A_t]}{[A_0]} =-kt](https://tex.z-dn.net/?f=ln%5Cfrac%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%20%3D-kt)
where;
At is the concentration of A at a time t
A₀ is the initial concentration of A
k is rate constant = 1.44×10⁻⁴ s⁻¹
t is time
ln(At/A₀) = -( 1.44×10⁻⁴)t
ln(At/0.125) = -( 1.44×10⁻⁴)210
ln(At/0.125) = -0.03024
At/0.125 = 0.9702
At = 0.125*0.9702
At = 0.121 M
Therefore, after 210 s the concentration of SO2Cl2 will be 0.121 M
Explanation:
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