Answer:

Explanation:
Considering,
Using ideal gas equation as:
where,
P is the pressure = 760 mmHg
V is the volume = 100.0 mL = 0.1 L
m is the mass of the gas = 0.193 g
M is the molar mass of the gas = ?
Temperature = 17 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (17 + 273.15) K = 290.15 K
R is Gas constant having value = 62.36367 L. mmHg/K. mol
Applying the values as:-
M = 45.95 g/mol
This mass corresponds to
. Hence, the gas must be
.
There is two of these questions
Answer:
You need two potassium atom to form an ionic bond with one sulfur atom. Pottassium ions are formed by donating losing their electrons in the outermost shell, thr lost electrons are gained by sulphur atom to form 2K+ and S2-, respectively. The attraction between the positive ions and negative ions gives rise to the ionic bond and the molecular formula is K2S
Explanation:
<u>Answer:</u> The value of
for the given chemical equation is 0.0457.
<u>Explanation:</u>
Given values:
Initial moles of
= 0.700 moles
Volume of conatiner = 3.50 L
The given chemical equation follows:

I: 0.700
C: -2x +2x x
E: 0.700-2x 2x x
Equilibrium moles of
= x = 0.180 moles
Equilibrium moles of
= 2x = 
Equilibrium moles of
= 0.700 - 2x = 
Molarity is calculated by using the equation:

So,
![[SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M](https://tex.z-dn.net/?f=%5BSO_3%5D_%7Beq%7D%3D%5Cfrac%7B0.340%7D%7B3.50%7D%3D0.0971M)
![[SO_2]_{eq}=\frac{0.360}{3.50}=0.103M](https://tex.z-dn.net/?f=%5BSO_2%5D_%7Beq%7D%3D%5Cfrac%7B0.360%7D%7B3.50%7D%3D0.103M)
![[O_2]_{eq}=\frac{0.180}{3.50}=0.0514M](https://tex.z-dn.net/?f=%5BO_2%5D_%7Beq%7D%3D%5Cfrac%7B0.180%7D%7B3.50%7D%3D0.0514M)
The expression of
for above equation follows:
![K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BSO_2%5D%5E2%5BO_2%5D%7D%7B%5BSO_3%5D%5E2%7D)
Plugging values in above expression:

Hence, the value of
for the given chemical equation is 0.0457.