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leva [86]
3 years ago
15

Two long, straight wires are fixed parallel to one another a distance do apart. The wires carry equal constant currents 1, in th

e same direction. The attractive magnetic force per unit length between them if f = F/L. What is the force per unit length between the wires if their separation is 2d, and each carries current 2I0?
A. f/4
B. f/2
C. 3f/2
D.) 2f
Physics
1 answer:
Mkey [24]3 years ago
4 0

Answer:

Option D

Explanation:

From the question we are told that:

The attractive magnetic force per unit length as

 f = F/L

Separation Distance x=2d

Generally the equation for  Magnetic force between two current carrying wire is mathematically given by

\frac{F}{\triangle l}=\frac{\mu_0I_1I_2}{\mu \pi x}

\frac{F}{\triangle l }=\frac{I_1I_2}{ x}

Where

x=2r

And

I_1=I_2=>2I

Then

\frac{F}{\triangle l}=>\frac{2*2}{2}*f

\frac{F}{\triangle l}=>2f

Therefore s the force per unit length between the wires if their separation is 2d

\frac{F}{\triangle l}=>2f

Option D

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