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2 years ago

Which law relates to any pushing or pulling applied to the body to create motion?

Physics

2 answers:

STALIN [3.7K]2 years ago

5 0

A force relates to any pushing or pulling applied to the body to create motion.

bazaltina [42]2 years ago

3 0

Answer:

force.

Explanation:

I just took the test

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Ms. PB is pushing Mr. Rigney in a wheelchair with a force of 10 N East, while Mr. Rigney is using his arms to

kumpel [21]

The net force is 6 N East

Explanation:

First of all, we start by noticing that all the forces act along the direction East-West, so we can simply find the net force by using algebraic addition.

In order to find the net force on the wheelchair, we need to define a positive direction and write down all the force with the proper sign.

Let's choose East as positive direction. Therefore, we have the following forces:

$F_1 = +10 N$ (east), the force applied by Ms. PB

$F_2 = +5 N$ (east), the force applied by Mr. Rigney

$F_f = -2 N$ (west), the frictional force, acting in the opposite direction

$F_r = -7 N$ (west), the air resistance, acting in the opposite direction

Taking into account the correct signs, we can now find the net force on the wheelchair:

$F=F_1+F_2+F_f+F_r = +10 + 5 +(-2) + (-7) = +6 N$

And the positive sign tells us that the direction of the net force is East.

Learn more about forces:

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brainly.com/question/6268248

#LearnwithBrainly

4 0

2 years ago

A planet is discovered orbiting around a star in the galaxy Andromeda at the same distance from the star as Earth is from the Su

aniked [119]

Answer:

The planet´s orbital period will be one-half Earth´s orbital period.

Explanation:

The planet in orbit, is subject to the attractive force from the sun, which is given by the Newton´s Universal Law of Gravitation.

At the same time, this force, is the same centripetal force, that keeps the planet in orbit (assuming to be circular), so we can put the following equation:

Fg = Fc ⇒ G*mp*ms / r² = mp*ω²*r

As we know to find out the orbital period, as it is the time needed to give a complete revolution around the sun, we can say this:

ω = 2*π / T (rad/sec), so replacing this in the expression above, we get:

Fg = Fc ⇒ G*mp*ms / r² = mp*(2*π/T)²*r

Solving for T²:

T² = (2*π)²*r³ / G*ms (1)

For the planet orbiting the sun in Andromeda, we have:

Ta² = (2*π)*r³ / G*4*ms (2)

As the radius of the orbit (distance to the sun) is the same for both planets, we can simplify it in the expression, so, if we divide both sides in (1) and (2), simplifying common terms, we finally get:

(Te / Ta)² = 4 ⇒ Te / Ta = 2 ⇒ Ta = Te/2

So, The planet's orbital period will be one-half Earth's orbital period.

7 0

2 years ago

On a horizontal axis whose unit is the meter, a linear load ranging from 0 to 1 ma a linear load distribution = 2 nC / m.

Dimas [21]

Answer:

The correct answer is - 8.99N/C

Explanation:

$dE=k\dfrac{dq}{x^2}\\ dq=\lambda{dx}\\ \lambda=2nC/m\\ dq=2dxnC\\ dE=k\dfrac{2dx}{x^2}\\ E=2k\int_1^2\dfrac{dx}{x^2}\\ E=2k(\frac{-1}{x})_1^2=k\times10^{-9}N/C\\ E=8.99\times10^9\times10^{-9}N/C\\ E=8.99N/C\\dE=k$

6 0

1 year ago

A car slows down uniformly from a speed of 21.0m/s to rest in 6.00s. How far did it travel in that time?

ss7ja [257]

(sorry something wrong w my keyboard so write each line for the explnation!)

63.0 m

Explanation:

Acceleration of car

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0 ms

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21.0 ms

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6.00 s

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3.50 ms

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(

0 ms

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)

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(

21.0 ms

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)

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3.50 ms

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63.0

4 0

2 years ago

The chemical reaction involved in burning wood is that endothermic or Exothermic?

kari74 [83]

Its Exothermic.......

3 0

2 years ago