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Reptile [31]
3 years ago
7

Please help with this!!

Chemistry
1 answer:
loris [4]3 years ago
8 0

Answer:

Limiting: Lab covers. Books produced: 75. Excess amounts: In explanation

Explanation:

Amount that can be produced with just lab covers: 75 books (150/2)

Amount that can be produced with just lined paper: 150 books (7500/50)

Amount that can be produced with graph paper: 120 (3000/25)

Amount that can be produced with staples: Approximately 83 (250/3)

As we can see, the lab covers are limiting as they can only produce 75 books. So, we can only make 75 books.

You will have 3,750 lined paper left over (or 75 books)

(150-75=75 , 75*50=3,750)

You will have 1,125 graph paper left over (or 45 books)

(120-75=45 , 75*25=1,875 , 3000-1875=1125)

And then you will have approximately 25 staples left over (or 8 books)

(83-75=8 , 8*3=225, 250-225=25)

(Hopefully this is correct, I apologize if I messed up)

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Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

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T2= 200  

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Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

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