Answer:
667.105ml
Explanation:
V1VP1 / V2P2
V2=V1P1 / P2
Pressure at S.T.P is 760
V2= 600×845/760
V2=667.105ml
Therefore V2 = 667.105ml approximately
I believe the answer would be Oratorio it was a concert piece not a musical theatre
Answer:
5.51g
Explanation:
Using the following formula:
Q = m × c × ∆T
Where;
Q = amount of heat in Joules
m = mass/weight of Aluminum
c = specific heat of Aluminum (0.900 J/g°C)
∆T = change in temperature.
Based on the information given in this question, Q = 175.6 joules, ∆T = 35.4°C, c = 0.900 J/g°C.
Using, Q = m × c × ∆T
175.6 = m × 0.900 × 35.4
175.6 = 31.86m
m = 175.6/31.86
m = 5.51g
The weight of the aluminum sample is 5.51g.
In order to compute this, we must first take a couple of assumptions of:
1) The laboratory size so we can calculate its volume
2) The number of students working in the lab so we know the total gas produced
Let the lab be
11 m × 9 m × 6 m
The volume then computes to be:
594 m³
We know that
1 Liter is 1 dm³
1 m = 10 dm
1 m³ = 1000 dm³
Therefore, the room volume in liters is:
594,000 Liters
Let there be 30 students in the laboratory
Total gas being produced:
6 × 30
= 180 Liters
This works out to be:
0.03% of Hydrogen by volume
Therefore, there is no risk of explosion given our assumption of size and students.
Answer:
i.elements not obeying increasing atomic mass. ii.properties and uneven grouping.