Answer:
A reasonable way to use them is to code the five most-common strings in the ... bytes, compared to a bitmap size of only 6 × 8 bits = 6 bytes. ... Columns 2, 4, 5, and 7 yield the six runs 0,5,1,1,1,eol each. ... 2.3: Replacing 10 by 3 we get x = k log2 3 ≈ 1.58k. ... Table Ans.3: Probabilities and Entropies of Two Symbols.
Step-by-step explanation:
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4 1/4 cup servings
hope this helps
Answer:
<h2>B. y= cos X</h2>
Step-by-step explanation:
<h2>Hope it help </h2>
<h2>Mark as brain liest and fo lllow</h2>
Answer:
which agrees with option"B" of the possible answers listed
Step-by-step explanation:
Notice that in order to solve this problem (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from 
, since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as 
and 
. (see attached image)
We put our efforts into solving the right angle triangle denoted with green borders.
Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by : 
Therefore, the two equal acute angles in the triangle JOH should add to:
resulting then in each small acute angle of measure 
.
Now referring to the green sided right angle triangle we can find find angle JLG, using: 
Finally, the requested measure of angle JLF is obtained via: 
Parallel means that the two equations have the same slope,
so we have y = 8x + b so far.
Then we can just apply the slope to the given point by taking the y value and decreasing it by 40, due to the x value being 5
So in short, the equation that runs parallel to y = 8x-8 and intersect the point (5,2) is y = 8x -38
