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xenn [34]
3 years ago
12

How to solve 9x-5-(-6x) ​

Mathematics
2 answers:
koban [17]3 years ago
6 0

Answer: 3x-5

Step-by-step explanation:

9x-5(-6x)

9x-5-6x

3x-5

Pavel [41]3 years ago
6 0

Answer:

15x - 5

Step-by-step explanation:

We have the equation 9x - 5 - (-6x) and are asked to solve it.

We cannot combine 9x and 5 because they have a variable difference, with 9 having x as its variable and 5 having no variable. What we can do is distribute the minus sign to the right of 5 to (-6x), lets do as said :

9x - 5 - (-6x)

Two negatives make a positive, therefore :

9x - 5 + 6x

Since 9x and 6x have the same variable ending, we can combine them, do as followed :

9x - 5 + 6x

9x + 6x

15x - 5

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349.76 in the bank after 11 years

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4 years ago
I. AM .SO. CONFUSED. HELP. PLZ.
dedylja [7]

Answer:

16mm

Step-by-step explanation:

Just do 40 * 2/5 = 80/5 = 16mm

3 0
4 years ago
1. The data given below includes data from 42 ​candies, and 7 of them are red. The company that makes the candy claims that 33​%
jeyben [28]

Answer:

The 95% confidence interval for true proportion of red candies is (5%, 27%).

The true proportion of red candies made by the company is different from 33%.

Step-by-step explanation:

The hypothesis to determine whether the claim made by the candy company is correct or not is:

<em>H</em>₀: The true proportion of red candies made by the company is 33%, i.e. <em>p</em> = 0.33.

<em>Hₐ</em>: The true proportion of red candies made by the company is different from 33%, i.e. <em>p</em> ≠ 0.33.

A (1 - <em>α</em>)% confidence interval can be constructed to check this claim.

The decision rule is:

If the confidence interval consists the null value then the null hypothesis will not be rejected. Otherwise it will be rejected.

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The information provided is:

<em>n</em> = 42

<em>X</em> = number of red candies = 7

Compute the sample proportion of candies that are red as follows:

\hat p=\frac{X}{n}=\frac{7}{42}=0.167

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table for the critical value.

Compute the 95% confidence interval for true proportion of red candies as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.167\pm 1.96\times \sqrt{\frac{0.167(1-0.167)}{42}}\\=0.16\pm0.1137\\=(0.0463, 0.2737)\\\approx(0.05, 0.27)

The 95% confidence interval for true proportion of red candies is (5%, 27%).

The confidence interval does not contains the null value.

Thus, the null hypothesis will be rejected at 5% level of significance.

Conclusion:

The true proportion of red candies made by the company is different from 33%.

7 0
3 years ago
What is 1/10 of an income of $97.50?
melisa1 [442]
9.75 dollars is the correct answer

Can you plz mark as brainliest
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Line JK passes through points j(-4, -5) and k(-6,3) If The Equations of the line is written in slope intercept form y=mx+b what
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Asked and answered elsewhere.
brainly.com/question/10440096

The value of b is -21.
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