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2 years ago

Question 2

Physics

2 answers:

Tju [1.3M]2 years ago

8 0

B. True give me branliest

ollegr [7]2 years ago

6 0

Answer:

Its False

Explanation:

In parallel circuits the current splits up so each branch has a different effective resistance (in each of the separate branches one can use the series rule again). Due to this, <u>the current isn't the same everywhere in a parallel circuit.</u>

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The 10-kg block is held at rest on the smooth inclined plane by the stop block at A. If the10-g bullet is traveling at 300m/swhe

WARRIOR [948]

Answer:

6.8 mm

Explanation:

We are given that

Mass of block,m=10 kg

Mass of bullet, $m_b=10 g=10\times 10^{-3} kg$

1 kg=1000 g

Total mass of system,M= $m+m_a=10+10\times 10^{-3}=10.01kg$

Speed of bullet,u=300 m/s

$\theta=30^{\circ}$

By law of conservation of momentum

$m_bucos\theta=Mv$

$v=\frac{m_bvcos\theta}{M}=\frac{0.01\times 300cos30^{\circ}}{10.01}=0.259m/s$

According to law of conservation of energy

Change in kinetic energy of system=Change in potential energy of system

$\frac{1}{2}Mv^2-0=Mgh-0$

$\frac{1}{2}(10.01)(0.259)^2=10.01\times 9.8 h$

Where $g=9.8 m/s^2$

$h=\frac{(0.259)^2}{2\times 9.8}=0.0034m$

1m=100 cm

$h=0.0034\times 100=0.34 cm$

Distance traveled by block= $d=\frac{h}{sin\theta}=\frac{0.34}{sin30^{\circ}}=0.68 cm=6.8 mm$

1cm=10 mm

4 0

3 years ago

A small grinding wheel is attached to the shaft of an electric motor which has a rated speed of 3600 rpm. When the power is turn

dolphi86 [110]

Answer:

(a) θ1 = 942.5rad, (b) θ2 = 13195 rad

Explanation:

(a) Given

ωo = 0 rad/s

ω = 3600rev/min = 3600×2(pi)/60 rad/s

ω = 377rad/s

t1 = 5s

θ1 = (ω + ωo)t/2

θ1 = (377 +0)×5/2

θ1 = 942.5 rads

(b) ωo = 377rad/s

ω = 0 rad/s

t2 = 70s

θ2 = (ω + ωo)t/2

θ2 = (377 +0)×70/2

θ2 = 13195 rad

6 0

3 years ago

A satellite dish is in the shape of a parabolic surface. Signals coming from a satellite strike the surface of the dish and are

RSB [31]

Answer: 6.125 ft

Explanation:

If this dish has the form of a concave upward parabola and its vertex $p$ is at the origin, its corresponding equation is:

$x^{2}=4py$

Where:

$x$ is the radius, which can be found by dividing the diameter $d=14 ft$ by half. Hence $x=\frac{d}{2}=\frac{14 ft}{2}=7 ft$

$y=2 ft$ is the depth

$p$ is the vertex of the parabola, where its base is

Finding $p$ :

$p=\frac{x^{2}}{4y}$

$p=\frac{(7 ft)^{2}}{4(2 ft)}$

Finally:

$p=6.125 ft$ This is where the the receiver should be placed

3 0

3 years ago

A 3.0N force to the right acts on a 0.5kg object at rest during a time interval of 4.0 seconds .What is the velocity of the obje

monitta

Answer:

24 m/s

Explanation:

Applying Newton's second law of motion,

F = ma................ Equation 1

Where F = force acting on the object, m = mass of the object a = acceleration of the object.

First we calculate for a.

make a the subject of the formula in equation 1 above

a = F/m............... Equation 2

Given: F = 3 N, m = 0.5 kg.

Substitute into equation 2

a = 3/0.5

a = 6 m/s²

Secondly we calculate the velocity by using,

v = u+at................... Equation 3

Where v = Final velocity of the object, u = initial velocity of the object, t = time interval

Given: u = 0 m/s (at rest), a = 6 m/s², t = 4 s

Substitute into equation 3

v = 0+6(4)

v = 24 m/s

5 0

3 years ago

Read 2 more answers

A ball that rolls on the ground is initially propelled with a speed of 45 km / h and after 10 seconds it stops. Assuming you los

solmaris [256]

Answer:

a) -1.25 m/s²

b) 62.5 m

Explanation:

Convert km/h to m/s:

45 km/h × (1000 m/km) × (1 h / 3600 s) = 12.5 m/s

a = Δv / Δt

a = (0 m/s − 12.5 m/s) / 10 s

a = -1.25 m/s²

Δx = ½ (v + v₀) t

Δx = ½ (0 m/s + 12.5 m/s) (10 s)

Δx = 62.5 m

5 0

2 years ago