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ivanzaharov [21]
3 years ago
9

What happens as the frequency of a wave increases?

Physics
2 answers:
topjm [15]3 years ago
8 0

Answer:

The number of complete wavelengths in a given unit of time is called frequency (f). As a wavelength increases in size, its frequency and energy (E) decrease. From these equations you may realize that as the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer.

Explanation:

please mark me as brainliest thank you

Firlakuza [10]3 years ago
5 0
As a wave increases, the frequency of the wave increases
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Difference between displacement and vector quantity
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The only 'difference' is that they are different categories.

It's like asking "What's the difference between Susie and girl ?"

Or "What's the difference between Cadillac and car ?"

Displacement <em>IS</em> a vector quantity.

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If a point charge is brought into an electric field then the electric field at a
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A spaceship maneuvering near planet zeta is located at r⃗ =(600i^−400j^+200k^)×103km, relative to the planet, and traveling at v
slava [35]

<u>Answer:</u>

 The spaceship's position when the engine shuts off = (708.15 i - 444.1 j + 200 k)*10^3km

<u>Explanation:</u>

  Initial location of spaceship = (600 i - 400 j + 200 k)*10^3km= (600 i - 400 j + 200 k)*10^6m

  Initial velocity = 9500 i m/s

  Acceleration = (40 i - 20 k)10^3m/s^2

  Time = 35 minute = 35 * 60 = 2100 seconds

 We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

  Substituting

       s= (9500 i)*2100+\frac{1}{2}*(40 i - 20 k)*2100^2\\ \\ s=9500*2100 i+20*2100^2i-10*2100^2j\\ \\ s=19.95*10^6i+88.2*10^6i-44.1*10^6j\\ \\ \\s=(108.15i-44.1j)*10^6m

     So final position = ((600 i - 400 j + 200 k)+(108.15i-44.1j))*10^6=(708.15 i - 444.1 j + 200 k)*10^6m

                              =(708.15 i - 444.1 j + 200 k)*10^3km

    The spaceship's position when the engine shuts off = (708.15 i - 444.1 j + 200 k)*10^3km

3 0
3 years ago
Read 2 more answers
a man exerts 3000.00N of force to push a car 35.00 meters in 90.00 seconds.... 1. what is the work done 2.what is the power gene
vaieri [72.5K]
1).  Work = (force) x (distance)

Work = (3,000 newtons) x (35 meters) = 105,000 newton-meters = <em>105,000 joules</em>

2).  Power = (work) / (time)

Power = (105,000 joules) / (90 seconds)
                                         = 1,166-2/3 joules per second =<em> 1,166 and 2/3 watts</em> .

<em>Note:</em>
That's no ordinary man.
1,166 watts is the same as roughly 1.6 horsepower.
Not too many people can sustain 1 horsepower or more for 90 seconds.




4 0
4 years ago
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