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Natali [406]
3 years ago
5

Will's suitcase must weigh less than 50 pounds. Choose the inequality that best represents the situation. a: x ≤ 50 b: a<50

Mathematics
1 answer:
emmasim [6.3K]3 years ago
3 0

Answer:

A

Step-by-step explanation:

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Melissa Silva borrowed $6,300 from the bank. If she has already repaid
melamori03 [73]
The remaining balance would be $3,600.

$6,300/7 = 900 x 3 = $2,700
$6,300 - $2,700 = $3,600
8 0
2 years ago
Solve the equation for a.
Pavel [41]

Answer:

\large\boxed{a=\dfrac{K}{4+9b}}

Step-by-step explanation:

K=4a+9ab\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\K=a(4+9b)\qquad\text{divide both sides by}\ (4+9b)\neq0\\\\\dfrac{K}{(4+9b)}=\dfrac{a(4+9b)}{(4+9b)}\\\\\dfrac{K}{4+9b}=a

6 0
3 years ago
Read 2 more answers
The endpoints of ab are a(1,4) and b(6,-1). If point c divides ab in the ratio 2:3, the coordinates of c are ?. If point d divid
aliya0001 [1]

Answer:

see explanation

Step-by-step explanation:

Find the coordinates of c using the section formula

x_{c} = \frac{(3(1)+(2(6)}{2+3} = \frac{3+12}{5} = 3

y_{c} = \frac{(3(4))+(2(-1))}{2+3} = \frac{12-2}{5} = 2

coordinates of c = (3, 2)

Similarly to find the coordinates of d

x_{d} = \frac{x(2(1))+(3(3))}{3+2} = \frac{2+9}{5} = \frac{11}{5}

y_{d} = \frac{(2(4))+(3(2))}{3+2} = \frac{8+6}{5} = \frac{14}{5}

coordinates of d = ( \frac{11}{5}, \frac{14}{5})


4 0
2 years ago
Read 2 more answers
Can you help with this?
g100num [7]

Answer:

c or d

Step-by-step explanation:

good luck

hope this helps

need more answer? just follow me

and it will be nice if i get Brainliest!!

8 0
2 years ago
HELPP!!!!!!!!!!!!!!!!
Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step.  The equation is

8-3\sqrt[5]{x^3}=-7

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time.  First thing is to subtract 8 from both sides:

-3\sqrt[5]{x^3}=-15

The goal is to isolate the term with the x in it, so that means that the -3 has to go.  Divide it away on both sides:

\sqrt[5]{x^3}=5

Let's rewrite that radical into exponential form:

x^{\frac{3}{5}}=5

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely.  On the right, let's rewrite that back in radical form to solve it easier:

x=\sqrt[3]{5^5}

Let's group that radicad into groups of 3's now to make the simplifying easier:

x=\sqrt[3]{5^3*5^2} because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

x=5\sqrt[3]{5^2} which is the same as:

x=5\sqrt[3]{25}

8 0
2 years ago
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