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Sloan [31]
3 years ago
14

How is shooting a shotgun related to newtons third law ? why does a rifle have less “kick” then a shotgun ?

Physics
1 answer:
Mazyrski [523]3 years ago
5 0
Newton’s third law is a force is a push or pull that acts upon an object as a result of another object.. A shot gun when fired pulls back when a force (you pulling the trigger) is acted upon it. This is how it relates. A rifle has less kick than a shot gun because the rifle is smaller and has less of a force than a shot gun.
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The correct answer is Contact force:)
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What is the magnitude of the force a 25 charge exerts on a 3 mc charge 35cm away?
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The electrostatic force between two charges is given by
F=k_e  \frac{q_1 q_2}{r^2}
where
ke is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the charges

In our problem, 
q_1 = 25 \mu C=25 \cdot 10^{-6} C
q_2 = 3 mC = 3 \cdot 10^{-3} C
r=35 cm=0.35 m
Therefore the electrostatic force is
F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(25 \cdot 10^{-6}C)(3 \cdot 10^{-3}C)}{(0.35 m)^2}= 5510 N
4 0
4 years ago
Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to
aev [14]

Answer:

D. Test a cell phone's reception in the exact same location under various atmospheric conditions

Explanation:

Components of an experiment:

Independent variable:

A manipulated variable, in an experiment or study, whose presence or degree incurs a change in the  dependent variable.

Dependent variable:

A variable which is being studied in the experiment and is supposed to change with respect to the independent variable.

Control variable:

Control variable includes the variables which are of no concern in the experiment and must be constant so that they do not interfere with the results of the experiment. Change in control variable might affect the results of an experiment.

In Anna's experiment, the independent variable is the atmospheric conditions. The dependent variable is cell phone reception that will change according to the atmospheric conditions. All other things related to the experiment are control variables like cellphone, location of the cell phone. Both of these must stay constant to collect the best data.

Hence, the best option is D.

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Talja [164]

Answer:

1. Distance travelled = 12 km.

2. Displacement = 8.6 km

Explanation:

From the question given above, the following data were obtained:

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance =?

Displacement =?

1. Determination of the distance travelled.

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance (dₜ) =?

dₜ = d₁ + d₂

dₜ = 7 + 5

dₜ = 12 km

2. Determination of the displacement.

In the attached photo, R is the displacement.

We can obtain the value of R by using the pythagoras theory as illustrated below:

R² = 7² + 5²

R² = 49 + 25

R² = 74

Take the square root of both side

R = √74

R = 8.6 km

8 0
3 years ago
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