19.7 litre volume of carbon dioxide gas at 22.0o C and 102 kPa can be collected over water.
<h3>What is vapour pressure?</h3>
Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.
Moles of Butane = mass in grams / molar mass = 11.6 / 58.12 = 0.2
Volume of
(V) = 40 liter
Temperature (T) = 22°C = 22 + 273 = 295 K
Pressure (P) = 102 kPa = 102 / 101.325 = 1.007 atm
Moles of
(n) can be calculated by ideal gas equation.
PV = nRT
n = 1.007 40 ÷ 0.0821 295 = 1.663
Balanced chemical reaction;
2
+ 13
---> 8
+ 10![H_2O](https://tex.z-dn.net/?f=H_2O)
From reaction;
13 moles
require 2 moles ![C_4H_10](https://tex.z-dn.net/?f=C_4H_10)
So, 1.663 moles
will require = 2 x 1.663 ÷13 = 0.256 moles of ![C_4H_10](https://tex.z-dn.net/?f=C_4H_10)
Thus
is a limiting reagent. So it will drive the yield of
.
Moles of
produced = (8/2) 0.2 = 0.8 moles
Pressure of
(P) = 102 - 2.24 = 99.76 kPa = 99.76 ÷ 101.325 = 0.985 atm
Applying the ideal gas equation for
,
PV = nRT
0.985 V = 0.8 0.0821 x 295
V = 19.7 liter
The volume of
produced = 19.7 liter.
Learn more about the vapour pressure here:
brainly.com/question/25699778
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