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Misha Larkins [42]
3 years ago
5

Who will it benefit if they do butterfly groin stretch​

Physics
2 answers:
Natali5045456 [20]3 years ago
4 0

Answer:

It is a great stretch for athletes who play field or court sports, runners, and anyone who has tight hips or a history of groin injuries.

Its a great flexibility exercise

Explanation:

Hope that helps

igor_vitrenko [27]3 years ago
3 0

Answer:

ummmmm mmmmm butterflies :)

Explanation:

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A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.4 m/s, a typical raindrop speed. How fast
kenny6666 [7]

The final velocity after the collision is 8.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, if we consider the system to be isolated (=no external unbalanced forces), the total momentum of the raindrop+mosquito must be conserved before and after the collision.

If the collision is perfectly inelastic, moreover, the raindrop and the mosquito stick together and travel at the same velocity v after the collision.

Mathematically:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 is the mass of the first mosquito

u_1 = 0 is the initial velocity of the mosquito

m_2 = 50 m_1 is the mass of the raindrop

u_2 = 8.4 m/s is the initial velocity of the raindrop

v is the final combined velocity of the raindrop+mosquito

Re-arranging the equation and substituting, we find:  

m_1 u_1 + 50 m_1 u_2 = (m_1 + 50 m_1) v\\50 m_1 u_2 = 51 m_1 v\\50 u_2 = 51 v\\v=\frac{50}{51}u_2 = \frac{50}{51}(8.4)=8.2 m/s

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4 0
4 years ago
Which of the following scenarios will cause the current to stop flowing within a current​
ella [17]

Answer:

The switch within the closed circuit is opened and it stops the flow of current in a circuit.

Explanation:

  • Current is defined as a flow of electrons in a system or a circuit.
  • There are two basic things needed for current to flow in a system
  • One is the electro-motive force and the other is the complete path for current to flow.
  • If a switch in a closed circuit gets opened, it restricts the path of current flow.
  • Thus it stops the current to be flowed through the circuit.
7 0
3 years ago
The diagram below shows the force exerted on object m1 due to the gravitational attraction between m1 and m2. What is true about
gladu [14]

Answer: B. It is directed to the left.

Explanation:

Gravitational force is an attractive force, this is stated by Newton's law of Gravitation:

<em>"The force exerted between two bodies of masses m1 and m2 and separated by a distance  is equal to the product of their masses and inversely proportional to the square of the distance"</em>

This means both m1 and m2 are mutually attracted.

Hence, if the force exerted on m1 by m2 is directed to the right, the force exerted on m2 by m1 must be logically <u>directed to the left.</u>

8 0
3 years ago
A particular milliampere-seconds value, regardless of the combination of milliamperes and time, will reproduce the same radiogra
finlep [7]

Answer:

C. Reciprocity law

Explanation:

The reciprocity law is based on the assumption that the density or blackening of a photographic film is dependent merely on the exposure or quantity of radiant energy which the film absorbs and is independent of the rate at which the energy is applied.

This law pertains to the milliampere-seconds in the sense that all combinations of milliamperes and time  that amount to an equal quantity will produce the same amount of radiographic density.

The answer is:

C. Reciprocity law

3 0
3 years ago
The SAF operates the M113 Ultra APC.
HACTEHA [7]

The volume of the object must be no larger than 11.15 m^3.

Explanation:

In order for an object to be able to float in water, its density must be equal or smaller than the water density.

The density of water is:

\rho = 1000 kg/m^3

This means that the density of the object must be no larger than this value.

We also know that the density of an object is given by

\rho = \frac{m}{V}

where

m is the mass of the object

V is its volume

For the object in this problem, the mass is

m=1.115\cdot 10^4 kg

Therefore, we can re-arrange the equation to find its volume:

V=\frac{m}{\rho}=\frac{1.115\cdot 10^4}{1000}=11.15 m^3

So, the volume of the object must be no larger than 11.15 m^3.

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8 0
4 years ago
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