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3 years ago

Who will it benefit if they do butterfly groin stretch

Physics

2 answers:

Natali5045456 [20]3 years ago

4 0

Answer:

It is a great stretch for athletes who play field or court sports, runners, and anyone who has tight hips or a history of groin injuries.

Its a great flexibility exercise

Explanation:

Hope that helps

igor_vitrenko [27]3 years ago

3 0

Answer:

ummmmm mmmmm butterflies :)

Explanation:

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The drift velocity should be in the same direction as the applied force. a. true b. false

Marina CMI [18]

It is a false statement i.e. drift velocity is not same in the direction as the applied force.

Drift velocity of a current-carrying conductor can be explained as, the charges i.e. electrons do not flow in the same direction of current. In other word, in most cases the movement of the electrons is almost random, with a small net velocity. So that , the drift velocity, in the direction opposite to the electric field.

Drift velocity $v_{d}$ is inversely proportional to the number of electron per unit volume of the conductor e. Therefore, the formulation can be given as ,

$v_{d}$ = σ E/ne

The above equation shows the drift velocity in a current carrying conductor

where, $v_{d}$ is drift velocity , σ is the conductivity, E is electric force and n is number of electrons per unit volume of the conductor e.

Hence here we can say that, the drift velocity is not in the same direction as the applied force.

To know more about drift velocity

brainly.com/question/17167604

#SPJ4

4 0

2 years ago

Neon is compressed from 100 kPa and 24°C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and

trasher [3.6K]

Answer:

ΔV = -0.97 m³/ kg

ΔH = 0 kJ/ kg

Explanation:

To determine the change in the specific volume we need to use the ideal gas law:

$PV = RT$

where P: pressure of the gas V: volume of the gas, R: ideal gas constant= 0.4119 kJ/kg.K = 0.4119 kPa.m³/kg.K and T: temperature of the gas.

The V₁, at a compressed pressure is:

$V_{1}= \frac {RT}{P_{1}}$

$V_{1}= \frac {0.4119 \frac{kPa\cdot m^{3}}{kg\cdot K} \cdot (24 + 273 K)}{100 kPa}$

$V_{1}= 1.22 \frac{m^{3}}{kg}$

Similarly, the V₂ is:

$V_{2}= \frac {RT}{P_{2}}$

$V_{2}= \frac {0.4119 \frac{kPa\cdot m^{3}}{kg\cdot K} \cdot (24 + 273 K)}{500 kPa}$

$V_{2}= 0.25 \frac{m^{3}}{kg}$

Now, the change in the specific volume because the compressor is:

$V_{2} - V_{1} = 0.25 - 1.22 \frac{m^{3}}{kg}$

$V_{2} - V_{1} = -0.97 \frac{m^{3}}{kg}$

Finally, to calculate the change in the specific enthalpy, we need to remember that neon is an ideal gas and that is an isothermal process:

$\Delta H = C_{p} \cdot \Delta T$

$\Delta H = 1.0299 \frac{kJ}{kg \cdot K} \cdot 0$

$\Delta H = 0 \frac{kJ}{kg}$

Have a nice day!

7 0

4 years ago

Which lobes of the brain receive the input that enables you to feel someone scratching your back? (2 points)

andrew-mc [135]

Answer: Parietal

Explanation: The parietal lobe is where the primary somatosensory cortex is located. This cortex is where all tactile stimulation is processed in the brain and allows to you detect/feel someone scratching your back.

3 0

3 years ago

What effects the amount of lift a plane gets?

vesna_86 [32]

Answer:

The airfoil shape and wing size will both affect the amount of lift. The ratio of the wing span to the wing area also affects the amount of lift generated by a wing. ... The lift then depends on the velocity of the air and how the object is inclined to the flow. Air: Lift depends on the mass of the flow.

Please give brainliest!!!

5 0

3 years ago

An object moves at constant speed in a circle. Which of the following is true:

shusha [124]

The answer to your question is B

3 0

3 years ago

Who will it benefit if they do butterfly groin stretch​

Who will it benefit if they do butterfly groin stretch