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2 years ago

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Describe one way in which light acts like a wave and one way in which light acts like a particle.

1 answer:

monitta2 years ago

3 0

Answer:

Quantum mechanics tells us that light can behave simultaneously as a particle or a wave. ... When UV light hits a metal surface, it causes an emission of electrons. Albert Einstein explained this "photoelectric" effect by proposing that light – thought to only be a wave – is also a stream of particles.

Explanation:

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In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested travelin

alexandr402 [8]

Answer:

a) $v=0.999124c$

b) $E=7.566*10^{22}$

c) $E_a=760 times\ larger$

Explanation:

From the question we are told that

Distance to Betelgeuse $d_b=430ly$

Mass of Rocket $M_r=20000$

Total Time in years traveled $T_d=36years$

Total energy used by the United States in the year 2000 $E_{2000}=1.0*10^20$

Generally the equation of speed of rocket v mathematically given by

$v=\frac{2d}{\triangle t}$

$v=860ly/ \triangle t$

where

$\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}$

$\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}$

$\triangle t=\sqrt{(860)^2+(36)^2}$

$\triangle t=860.7532$

Therefore

$v=\frac{860ly}{ 860.7532}$

$v=0.999124c$

b)

Generally the equation of the energy E required to attain prior speed mathematically given by

$E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2$

$E=7.566*10^{22}$

c)Generally the equation of the energy $E_a$ required to accelerate the rocket mathematically given by

$E_a=\frac{E}{E_{2000}}$

$E_a=\frac{7.566*10^{22}}{1.0*10^{20}}$

$E_a=760 times\ larger$

8 0

3 years ago

A machine has an efficiency of 70%. How much work dose the machine do when 20,000 J of work is done on it ?

Murrr4er [49]

Answer: The machine does 14.000 J

3 0

3 years ago

A pendulum Bob released from some initial height such that the speed of the bob at the bottom of the swing is 1.9m/s. What is th

Dmitriy789 [7]

Answer:

h = 18.4 cm

Explanation:

Given that,

The speed of the bob at the bottom of the swing is 1.9m/s.

We need to find the initial height of the bob. Let it is h.

We can find it using the conservation of energy i.e.

$mgh=\dfrac{1}{2}mv^2$

Where

v is speed of the bob

So,

$h=\dfrac{v^2}{2g}\\\\h=\dfrac{(1.9)^2}{2\times 9.8}\\\\h= 0.184\ m$

or

h = 18.4 cm

So, the initial height of the bob is 18.4 cm.

8 0

2 years ago

The water waves below are traveling along the surface of the ocean at a speed of 2.5 m/s and

gavmur [86]

Answer:2 seconds

Time= Distance/speed

=50/25

=2seconds

3 0

2 years ago

Which labels correctly identify the layers most closely associated with gamma rays and visible light? Z: Gamma rays X: Visible l

Marianna [84]

The answer is Z: Gamma rays X: Visible light. Gamma ray is the shortest and has the greatest frequency and power. That is why it is in letter Z.

4 0

3 years ago