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matrenka [14]
4 years ago
8

When the moon is directly between the Earth and sun, it is called a _____ eclipse.

Physics
2 answers:
sleet_krkn [62]4 years ago
5 0
C. solar I believe because of the sun is touching the Moons back like hey little buddy
user100 [1]4 years ago
4 0
I think It’s a lunar eclipse
Sorry if I’m wrong

Explanation

When the Moon passes between Sun and Earth, the lunar shadow is seen as a solar eclipse on Earth. When Earth passes
directly between Sun and Moon, its shadow creates a lunar eclipse. Lunar eclipses can only happen when the Moon is opposite the Sun in the sky, a monthly occurrence we know as a full Moon.

Hope it helps!
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Determine the empirical formula for a compound that is 36.86% n and 63.14% o by mass.
olga2289 [7]

Answer:

NO_{1.499}

Explanation:

Let assume that 100 kg of the compound is tested. The quantity of kilomoles for each element are, respectively:

n_{N} = \frac{36.86\,kg}{14.006\,\frac{kg}{kmol} }

n_{N} = 2.632\,kmol

n_{O} = \frac{63.14\,kg}{15.999\,\frac{kg}{kmol} }

n_{O} = 3.946\,kmol

Ratio of kilomoles oxygen to kilomole nitrogen is:

n^{*} = \frac{3.946\,kmol}{2.632\,kmol}

n^{*}= 1.499

It means that exists 1.499 kilomole oxygen for each kilomole nitrogen.

The empirical formula for the compound is:

NO_{1.499}

8 0
4 years ago
Read 2 more answers
Different objects don't heat at the same rate because they have different
Kaylis [27]
Specific heat

Let me know if you need further explanation!
7 0
3 years ago
I need help finding the solution
omeli [17]

Answer:

objects with greater mass should have greater inertia

6 0
3 years ago
A proton of mass is released from rest just above the lower plate and reaches the top plate with speed . An electron of mass is
xenn [34]

Answer:

  v = √ 2e (V₂-V₁) / m

Explanation:

For this exercise we can use the conservation of the energy of the electron

At the highest point. Resting on the top plate

         Em₀ = U = -e V₁

At the lowest point. Just before touching the bottom plate

        Emf = K + U = ½ m v² - e V₂

Energy is conserved

         Em₀ = Emf

          -eV₁ = ½ m v² - e V₂

           v = √ 2e (V₂-V₁) / m

Where e is the charge of the electron, V₂-V₁ is the potential difference applied to the capacitor and m is the mass of the electron

3 0
4 years ago
How to find the frictional force acting on an object (not the friction coefficient)? ...?
Dovator [93]
One can simply find the frictional force acting on an object using this equation:

 (Ffrict<span> = μ•F</span>norm<span>)
</span>

The process of determining the value of the individual forces acting upon an object involve an application of Newton's second law (Fnet=m•a) and an application of the meaning of the net force. If mass (m) and acceleration (a) are known, then the net force (Fnet) can be determined by use of the equation.

<span>Fnet = m • a</span>

If the numerical value for the net force and the direction of the net force is known, then the value of all individual forces can be determined.

7 0
4 years ago
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