The force exerted by gravity on 5kg=~ n

Niobium metal becomes a superconductor (with zero electrical resistance) when cooled below 5.1 K. The permeabilty of free space

katovenus [111]

Answer:

687.5 A

Explanation:

We are given that

$\mu_0=1.25664\times 10^{-6}N/A^2$

Magnetic field,B=0.11 T

Diameter,d=2.5mm

Radius,r= $\frac{d}{2}=\frac{2.5}{2}mm=1.25\times 10^{-3} m$

$1mm=10^{-3} m$

We know that current in coil

$I=\frac{2\pi rB}{\mu_0}$

Substitute the values

$I=\frac{2\pi\times 1.25\times 10^{-3}\times 0.11}{1.25664\times 10^{-6}}$

$I=687.5 A$

8 0

3 years ago

Throw two balls from the same height at the same time at an initial speed of 20 m/s. One is thrown vertically down, while the ot

labwork [276]

The time difference between their landing is 2.04 seconds.

<h3>Time of difference of the two balls</h3>

The ball thrown vertical upwards will take double of the time taken by the ball thrown vertically downwards.

Time difference, = 2t - t = t

t = √(2h/g)

where;

h is the height of fall
g is acceleration due to gravity

Apply the principle of conservation of energy;

¹/₂mv² = mgh

h = v²/2g

where;

v is speed of the ball

h = (20²)/(2 x 9.8)

h = 20.41 m

<h3>Time of motion</h3>

t = √(2 x 20.41 / 9.8)

t = 2.04 s

Thus, the time difference between their landing is 2.04 seconds.

Learn more about time of motion here: brainly.com/question/2364404

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6 0

2 years ago

Use these relationships to determine the number of calories to change 1.5 kg of 0∘c ice water to 1.5 kg of 100∘c boiling water.

aivan3 [116]

The latent heat of fusion of water is 80 cal/g.
The specific heat of water is 1 cal/g-C.
The latent heat of vaporization of water is 540 cal/g.
Therefore, if we have 1.5 kg = 1500 g, the total heat requirement is:
1500 g[(80 cal/g) + (1 cal/g-C)(100 - 0)C + (540 cal/g)] = 1500 g(720 cal/g) = 1,080,000 cal.

4 0

3 years ago

A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse

NISA [10]

Answer:

The time interval is $t = 5.48 *10^{-3} \ s$