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Kay [80]
3 years ago
15

An upright clothes washer spins clothes around 30 times in 12 seconds. Its radius is 0.20m. What is the tangential velocity of t

he clothes in the washer?

Physics
2 answers:
ankoles [38]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

ziro4ka [17]3 years ago
4 0

Answer:

<em>3.142 m/sec</em>

Explanation:

Tangential velocity is the velocity measured along the path of a rotating body, which is tangent forms a tangent with the path.

The tangential velocity of the washer can be obtained using equation 1:

V = ω x r

where is the tangential velocity

ω is the angular velocity

r is the radius = 0.20 m.

Calculating for the angular velocity

ω = \frac{Number of revolutions}{time}

given the number of revolution as 30 and time 12 secs our angular velocity can be obtained as;

ω = \frac{30}{12 secs}

ω  = 2.5 rev/secs

angular velocity is measured in rad/sec so we have to convert our answer;

1 rev/sec = 2π rad/rev

2.5 rev/secs = 2π rad/rev x 2.5 re/secs = 15.71 rad/sec

the answer will be substituted into the expression in equation 1 to obtain the tangential velocity;

V = 15.71 rad/sec x 0.20 m

V = 3.142 m/sec

Therefore the tangential velocity of the washer is <em>3.142 m/sec</em>

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A 200g piece of iron is heated at 100C. It is than dropped into water to bring its temperature down to 22C. What is the amount o
gizmo_the_mogwai [7]

Answer:

6926.4J

Explanation:

Given parameters:

Mass of iron  = 200g

Initial temperature  = 100°C

Final temperature  = 22°C

Unknown:

Amount of heat transferred to the water  = ?

Solution:

The quantity of heat transferred to the water is a function of mass and temperature of the iron;

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m is the mass of the iron

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Now;

 insert the parameters and solve;

      H  = 200 x 0.444 x (100-22)

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8 0
3 years ago
A 747 airliner reaches its takeoff speed of 173 mi/h in 35.2 s. what is the magnitude of its average acceleration
wolverine [178]
<span>7.21 ft/s^2
       
Since you're looking for average acceleration, you can simply divide the change in velocity by the time. To make the calculation more reasonable, first convert the speed of 173 mi/h into ft/sec by multiplying by 5280 to convert from mi/h to ft/h and then dividing by 3600 to convert from ft/h to ft/s. 173 * 5280 / 3600 = 253.7333 ft/s Now divide the change in velocity by the time in seconds. 253.7333 ft/s / 35.2 s = 7.208333 ft/s^2 Rounding result to 3 significant figures gives 7.21 ft/s^2</span>
5 0
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A straight segment of wire 35.0 cm long carrying a current of 2.60 A is in a uniform magnetic field. The segment makes an angle
den301095 [7]

Answer:

Magnetic field, B = 0.275 T

Explanation:

Given that,

Length of the wire, L = 35 cm = 0.35 m

Current carried in the wire, I = 2.6 A

The segment makes an angle of 53∘ with the direction of the magnetic field, \theta=53^{\circ}

Magnetic force, F = 0.2 N

To find,

The magnitude of the magnetic field.

Solution,

The magnetic force acting on the wire is given by :

F=ILBsin\theta

\theta is the angle between the length of wire and the magnetic field.

0.2=2.6\times 0.35\times B\times sin(53)

B = 0.275 T

Therefore, the magnitude of the magnetic field is 0.275 T. Hence, this is the required solution.

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