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Kay [80]
3 years ago
15

An upright clothes washer spins clothes around 30 times in 12 seconds. Its radius is 0.20m. What is the tangential velocity of t

he clothes in the washer?

Physics
2 answers:
ankoles [38]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

ziro4ka [17]3 years ago
4 0

Answer:

<em>3.142 m/sec</em>

Explanation:

Tangential velocity is the velocity measured along the path of a rotating body, which is tangent forms a tangent with the path.

The tangential velocity of the washer can be obtained using equation 1:

V = ω x r

where is the tangential velocity

ω is the angular velocity

r is the radius = 0.20 m.

Calculating for the angular velocity

ω = \frac{Number of revolutions}{time}

given the number of revolution as 30 and time 12 secs our angular velocity can be obtained as;

ω = \frac{30}{12 secs}

ω  = 2.5 rev/secs

angular velocity is measured in rad/sec so we have to convert our answer;

1 rev/sec = 2π rad/rev

2.5 rev/secs = 2π rad/rev x 2.5 re/secs = 15.71 rad/sec

the answer will be substituted into the expression in equation 1 to obtain the tangential velocity;

V = 15.71 rad/sec x 0.20 m

V = 3.142 m/sec

Therefore the tangential velocity of the washer is <em>3.142 m/sec</em>

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\frac{I}{I_0}=113.68

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Ratio

\frac{I}{I_0}=\frac{\frac{63\times 10^{-6}}{4\times \pi \times 210^2}}{1\times 10^{-12}}\\\Rightarrow \frac{I}{I_0}=113.68

Ratio of the acoustic intensity produced by the juvenile howler to the reference intensity is 113.68

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Electric Current:

Electric current is the flow of charge through a given circuit per unit time. Electric current is one of the components needed to calculate the electric power that a device needs to operate and do work. Electric current is measured in amperes (A), which is equal to:

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Electricity is produced when an electric current runs through a circuit.

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A uniform disk of mass M = 4.9 kg has a radius of 0.12 m and is pivoted so that it rotates freely about its axis. A string wrapp
AlekseyPX

Answer:

(A) 2.4 N-m

(B) 0.035kgm^2

(C) 315.426 rad/sec

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(E) 725.481 rad

Explanation:

We have given mass of the disk m = 4.9 kg

Radius r = 0.12 m, that is distance = 0.12 m

Force F = 20 N

(a) Torque is equal to product of force and distance

So torque \tau =Fr, here F is force and r is distance

So \tau =20\times 0.12=2.4Nm

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So I=\frac{1}{2}\times 4.9\times 0.12^2=0.035kgm^2

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(E) From second equation of motion

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