What is the magnitude of the resultant vector? Round

List and explain Newton’s Laws of Motion. Give an example for each.

irga5000 [103]

Answer:

If you use the same force to push a truck and a car, the car will have more acceleration than the truck because the car has less mass.

It is easier to push an empty shopping cart than a full one, because the full shopping cart has more mass than the empty one. This means that more force is required to push the shopping cart.

When a person kicks a ball the person exerts force in a specific direction, that is the direction in which it will travel. In addition to this, the stronger the ball is kicked, the stronger the force we put on it and the further away it will travel.

Suppose two people are walking and among the two people, if one is heavier than the other, then the one weighing heavier will walk slower because the acceleration of the person weighing lighter is greater.

When riding a bicycle, the bicycle acts as mass and our leg muscles pushing on the pedals of the bicycle is the force.

Explanation:

8 0

3 years ago

Find the equilibrant of two 10.0-N forces acting upon a body when the angle between the forces is 90° Solve graphically using a

bazaltina [42]

The equilibrant force of the two given forces is 14.14 N.

<h3 /><h3 /><h3>What is equilibrant force?</h3>

This is a single force that balances other given forces.

The given parameters:

First force, F₁ = 10 N
Second force, F₂ = 10 N
Angle between the forces, θ = 90⁰

The equilibrant force of the two given forces is calculated as follows;

$F = \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{(10)^2 + (10)^2} \\\\F = 14.14 \ N$

Thus, the equilibrant force of the two given forces is 14.14 N.

Learn more about equilibrant force here: brainly.com/question/8045102

5 0

3 years ago

Which best compares the temperatures of the substance?

omeli [17]

The answer is C. Substance Y has the highest temperature because its particles have more kinetic energy.

6 0

3 years ago

Two 5.0-cm-diameter conducting spheres are 8.0 m apart, and each carries 0.12 mC. Determine (a) the potential on each sphere, (b

blagie [28]

Answer:

Explanation:

Two spheres 10m apart

Each charge on the sphere is 0.12mC= 0.12×10^-3C

Given that the diameter is

5cm=0.05m

Then, the radius is diameter / 2

r=d/2

r=0.05/2

r=0.025m

Potential is given as

V=kq/r

k=9×10^9Nm2/C2

a. Potential on each sphere surface.

They are going to have the same value since the sphere are identical

At the surface of the sphere,

r= 0.025m

V=kq/r

V=9E9×0.12E-3/0.025

V=4.32E7Volts

V=4.32×10^7Volts

b. The electric field at the surface of each sphere will be the same since the charge are identical,

So, Electric field is given as

E=kq/r^2

At the surface

E=9E9×0.12E-3/0.025^2

E=1.728×10^8N/C

c. The potential mid way between the two sphere

The potential difference due to the first sphere

The sphere are 10m apart then the distance mid way is 5m

Then, the radius of the sphere is 0.025m

Total distance from the center is 5.025m

Then,

V=kq/r

V1=9E9×0.12E-3/5.025

V1=2.149×10^5 Volts

Potential difference due to the second sphere is the same as the first, since both are identical

Total potential is V1 +V2

V=2.149E5+2.149E5

V=4.3E5Volts

Total potential at the middle due to the two sphere is 4.3×10^5Volts

d. The potential difference between the sphere at any point is equal to the potential difference found at c

Therefore the potential difference is

V=4.3×10^5Volts

4 0

3 years ago

A particle with charge -5 C initially moves at v = (1.00 i^ + 7.00 j^ ) m/s. If it encounters a magnetic field B =80 Tkˆ, find t

algol [13]

Answer:

The magnetic force is $\= F = 400\r j + 2800\r i$

Explanation:

From the question we are told that

The charge is $q = -5C$

The velocity is $v = (1.00\ \r i + 7.00 \ \r j )\ m/s$

The magnetic field is $B = 80 \r k \ \ T$

Generally the magnetic force is mathematically represented as

$\= F = q \= v \ \ X \ \ \= B$

=> $\= F = -5 (1.0 \r i + 7.0 \r j ) \ \ X \ \ 80 \r k$

=> $\= F = -5.0 \r i + 35\r j \ \ \ X \ \ 80\r k$

=> $\= F = 400\r j + 2800\r i$ N/B - Applied cross - product of unit vector

8 0

4 years ago