3 years ago

Velocity-time graph of an object is given below. The object has:

Physics

1 answer:

ziro4ka [17]3 years ago

8 0

Answer:

Explanation:

Because you have no values on this graph, the only thing one can possibly state about this graph is that the object is experiencing a negative acceleration.

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Explanation:

We have,

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$q(t) = 4t^3 + 5t + 6$

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$q(t) = 4t^3 + 5t + 6\\\\q(2) = 4(2)^3 + 5(2) + 6\\\\q=48\ C$

(b) Current is given by :

$I=\dfrac{dq}{dt}\\\\I=\dfrac{d(4t^3 + 5t + 6)}{dt}\\\\I=12t^2+5$

Instantaneous current at t = 1 s is,

$I=12(1)^2+5=17\ A$

Current density is given by electric current per unit area.

$J=\dfrac{I}{A}\\\\J=\dfrac{(12t^2+5)}{0.0002}\\\\J=5000(12t^2+5)\ A/m^2$

Therefore, it is the required explanation.

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