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3 years ago

What will be the acceleration of a body moving with uniform velocity?

Physics

1 answer:

Triss [41]3 years ago

8 0

Answer:

so the acceleration of the body would be zero because there is no change in velocity

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Number of atoms of each element potassium chlorate?

11111nata11111 [884]

5 atoms is the answer

6 0

3 years ago

Mercury has a density of 13.56 g/mL. How many kilograms of mercury would you expect to fit in a cylindrical glass cup with a bot

vovangra [49]

Answer:

263.152kg

Explanation:

The density of a substance is related to its mass and volume as follows;

density = mass / volume

mass = density x volume -------------(i)

The substance in question here is mercury which has;

density = 13.56g/mL = 13.56g/cm³

Since the mercury is going to be put in the cylindrical glass, the volume of the cylindrical glass is going to be equal to the volume of the mercury that will be put.

And we know that the;

volume of a cylinder = πr²h

Where;

π = 3.142

r = bottom radius of the cylinder = 5.75inches

h = height of the cylinder = 0.950ft

For uniformity, let's convert the radius and height of the cylinder to their corresponding values in cm

r = 5.75 inches = 5.75 x 2.54 cm = 14.605cm

h = 0.950 ft = 0.950 x 30.48 cm = 28.956cm

Therefore, the volume of the cylinder;

v = 3.142 x (14.605cm)² x 28.956cm = 19406.5cm³

v = 19406.5cm³ [This is also the volume of the mercury necessary to fit the cylinder]

Now the following value has been found;

volume = 19406.5cm³

Substitute the values of density and volume into equation (i) as follows;

mass = 19406.5cm³ x 13.56g/cm³

mass = 263152.14g

Convert the result to kg by dividing by 1000

mass = 263.152kg

Therefore, 263.152kg kilograms of mercury would fit in the cylindrical glass.

3 0

3 years ago

An electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat

irina [24]

Explanation:

The charge on the electron is, $q=-1.6\times 10^{-19}\ C$

The electric field at a distance r from the electron is :

$E=k\dfrac{q}{r^2}$

Where

k is the electrostatic constant, $k=\dfrac{1}{4\pi \epsilon_o}$

We know that the electric field lines starts from positive charge and ends at the negative charge. Also, for a positive charge the field lines are outwards while for a negative charge the field lines are inwards.

So, the correct option is " the electric field is directed toward the electron and has a magnitude of $k\dfrac{q}{r^2}$ . Hence, this is the required solution.

4 0

3 years ago

Which of the following correctly compares the uses of bar graphs versus pie charts?

slavikrds [6]

Bar graphs show data involved in distinct categories that do not overlap; whereas, pie charts show data as parts out of a whole (such as out of 100%).

6 0

3 years ago

What is the temperature of a star (in Kelvin) if its peak wavelength is 150 nm (that is, 150 x 10^-9 m)?

liq [111]

Answer:

19320 K

Explanation:

The temperature of a star is related to its peak wavelength by Wien's displacement law:

$T=\frac{b}{\lambda}$