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GalinKa [24]
3 years ago
7

An artificial sattelite is moving in a circular orbit of radius 42250km calculate its speed if it takes 24 hours to revolve arou

nd the earrth
Physics
1 answer:
vekshin13 years ago
5 0

Answer:

v = 11061.02 km/h

Explanation:

Given that,

The radius of the circular orbit, r = 42250 km

Time taken to revolve around the Earth, t = 24 hours

We need to find the speed of the satellite. We know that, speed of an object is equal to total distance traveled divided by the time taken. So,

v=\dfrac{2\pi r}{T}

Put all the values,

v=\dfrac{2\pi \times 42250}{24}\\\\v=11061.02\ km/h

So, the speed of the satellite is equal to 11061.02 km/h.

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13. Momentum is an object’s mass times velocity. Which has more momentum? A paper airplane with a mass of 10g flying at a veloci
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3 years ago
The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given b
Mnenie [13.5K]

Explanation:

The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by :

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We need to find the current flowing. We know that the rate of change of electric charge is called electric current. It is given by :

I=\dfrac{dQ}{dt}\\\\I=\dfrac{d(t^3-2t^2+4t+4)}{dt}\\\\I=3t^2-4t+4

At t = 1 s,

Current,

I=3(1)^2-4(1)+4\\\\I=3\ A

So, the current at t = 1 s is 3 A.

For lowest current,

\dfrac{dI}{dt}=0\\\\\dfrac{d(3t^2-4t+4)}{dt}=0\\\\6t-4=0\\\\t=0.67\ s

Hence, this is the required solution.

7 0
3 years ago
ماهي قوة التركيز من العين عندما ينضر الكاءن من ٢٠ الى ٥٠٠ من عينه
Debora [2.8K]

Answer:

What is the power of focus from the eye when a subject looks from 20 to 500 from its eye?

Explanation:

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4 0
2 years ago
Determine how many times per second it would move back and forth across a 6.0-m-long room on the average, assuming it made very
timofeeve [1]

Answer:

The right solution is "24.39 per sec".

Explanation:

According to the question,

⇒ v=\frac{502.1}{\sqrt{3} }

      =289.9 \ m/s

The time will be:

⇒ t=\frac{d}{v}

      =\frac{2\times 6}{289.9}

      =\frac{12}{289.9}

      =0.041 \ sec

hence,

⇒ N=\frac{1}{t}

        =\frac{1}{0.041}

        =24.39 \ per \ sec

4 0
2 years ago
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