Energy stored in the capacitor= 2.2 x 10⁻¹⁰ J
Explanation:
The energy stored in the capacitor is given by
E= 1/2 q V
E= energy stored
q= charge= 7.6 x 10⁻¹¹ C
V= potential difference=5.8 V
so energy stored= E= 1/2 (7.6 x 10⁻¹¹) (5.8)
Energy stored= 2.2 x 10⁻¹⁰ J
Answer:
Net electric field, 
Explanation:
Given that,
Charge 1, 
Charge 2, 
distance, d = 3.2 cm = 0.032 m
Electric field due to charge 1 is given by :



Electric field due to charge 2 is given by :



The point charges have opposite charge. So, the net electric field is given by the sum of electric field due to both charges as :



So, the electric field strength at the midpoint between the two charges is 91406.24 N/C. Hence, this is the required solution.
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Force is equal to mass multiplied by acceleration. Hope this helps!
Given that : d = 5sin(pi t/4), So, maximum displacement, d = 5*(+1) = 5 Also, maximum displacement, d = 5*(-1) = -5