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GalinKa [24]
3 years ago
7

An artificial sattelite is moving in a circular orbit of radius 42250km calculate its speed if it takes 24 hours to revolve arou

nd the earrth
Physics
1 answer:
vekshin13 years ago
5 0

Answer:

v = 11061.02 km/h

Explanation:

Given that,

The radius of the circular orbit, r = 42250 km

Time taken to revolve around the Earth, t = 24 hours

We need to find the speed of the satellite. We know that, speed of an object is equal to total distance traveled divided by the time taken. So,

v=\dfrac{2\pi r}{T}

Put all the values,

v=\dfrac{2\pi \times 42250}{24}\\\\v=11061.02\ km/h

So, the speed of the satellite is equal to 11061.02 km/h.

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Energy stored in the capacitor= 2.2 x 10⁻¹⁰ J

Explanation:

The energy stored in the capacitor is given by

E= 1/2 q V

E= energy stored

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so energy stored= E= 1/2 (7.6 x 10⁻¹¹) (5.8)

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A 7.5 nC point charge and a - 2.9 nC point charge are 3.2 cm apart. What is the electric field strength at the midpoint between
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Answer:

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Explanation:

Given that,

Charge 1, q_1=7.5\ nC=7.5\times 10^{-9}\ C

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distance, d = 3.2 cm = 0.032 m

Electric field due to charge 1 is given by :

E_1=\dfrac{kq_1}{r^2}

E_1=\dfrac{9\times 10^9\times 7.5\times 10^{-9}}{(0.032)^2}

E_1=65917.96\ N/C

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E_2=\dfrac{kq_2}{r^2}

E_2=\dfrac{9\times 10^9\times 2.9\times 10^{-9}}{(0.032)^2}

E_2=25488.28\ N/C

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E_{net}=E_1+E_2

E_{net}=65917.96+25488.28

E_{net}=91406.24\ N/C

So, the electric field strength at the midpoint between the two charges is 91406.24 N/C. Hence, this is the required solution.

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